Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck pending
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Entropy estimates for complex Gaussian interference converses

Statement

Assume AC, use base-two entropy, and let Zn,Wn be IID unit circular Gaussian vectors independent of Xn, where n−1∑jVar⁡(Xj)≤P. For s≥t≥0, h(sXn+Zn)−h(tXn+Wn)≤nlog⁡21+sP1+tP. For the complex channel in Real and complex two-user Gaussian interference channels, let the two input vectors be independent, obey the average power constraints, and have arbitrary dependence within each vector. Write a=SNR1, b=SNR2, c=INR1, d=INR2, S1n=h12X1n+Z2n, and S2n=h21X2n+Z1n. Then h(Y1n∣S1n)≤nlog⁡2 ⁣(πe[1+c+a1+d]),h(Y2n∣S2n)≤nlog⁡2 ⁣(πe[1+d+b1+c]), h(Y1n)≤nlog⁡2(πe[1+a+c]),h(Y2n)≤nlog⁡2(πe[1+b+d]), h(Y2n∣S2n,X1n)≤nlog⁡2 ⁣(πe[1+b1+c]), and the index-reflected conditional bound also holds.

Facts & Assumptions

Given: The finite-second-moment inputs, independent Gaussian noises, and average power bounds in the statement; entropy is measured in bits.

[A1]

The Axiom of Choice: AC is inherited through the Gaussian and information suppliers.

[F1]

Real and complex two-user Gaussian interference channels: the channel, SNR/INR convention, and average input power constraints.

[F2]

Circular complex Gaussian maximizes differential entropy at fixed second moment: after dividing its natural-log bound by ln⁡2, a complex variable of variance v with finite entropy and positive-definite real covariance has base-two entropy at most log⁡2(πev).

[F3]

Bounded densities with finite second moments have finite differential entropy: bounded densities of finite second moment have finite differential entropy.

[F4]

Conditional mutual-information chain rule and data processing for standard-Borel variables: conditional mutual-information chain rules, nonnegativity, and data processing.

[F5]

Measure-theoretic mutual information: mutual information is the natural-log KL divergence of the joint law from the product of its marginals, measured in nats.

Proof

1.1A1F2F3F4F5givenalgebra

If (T,S) are jointly Gaussian-smoothed finite-second-moment scalar variables with nonsingular joint Gaussian noise, then h(T∣S)=h(T−kS∣S)≤h(T−kS)≤log⁡2(πeVar⁡(T−kS)) for every complex k. The first identity is conditional translation and the first inequality is conditional mutual-information nonnegativity; the second is [F2]. A finite-dimensional convolution with a nonsingular Gaussian has a bounded density, finite second moment, and positive-definite real covariance; [F3], applied after identifying complex vectors with real vectors, therefore makes every relevant joint, marginal, and residual differential entropy finite and verifies the hypotheses of [F2]. In particular the pairs (Y1n,S1n) and (Y2n,S2n) have nonsingular independent receiver-noise coordinates, and the degraded pair below has nonsingular joint Gaussian noise when s>t. Their conditional entropies are differences of these finite joint and marginal entropies. For conditioning additionally on X1n, which need not have a density, first subtract its known translated contribution; independence removes that conditioning and leaves the nonsingular smoothed pair (h22X2n+Z2n,S2n). For a channel with conditional density w(t∣x) and positive output density fT(t), the joint-to-product density ratio is w(t∣x)/fT(t). Thus [F5] gives I(X;T)=∫ln⁡(w(t∣x)/fT(t)) dPX,T. When T=BX+Z with independent nonsingular Gaussian Z, the two log integrals are finite by [F3] and the quadratic Gaussian log density, and this integral equals (ln⁡2)[h(T)−h(Z)]. The same calculation with conditional densities justifies the conditional entropy identities used below, with every base-two entropy difference equal to the corresponding mutual information divided by ln⁡2, since their joint and marginal entropies are finite as established above. At zero signal power the same Gaussian density argument applies without alteration. Coordinate entropy chain rules give h(Tn∣Sn)≤∑jh(Tj∣Sj).

2.1F4F5step 1.1givenconstructalgebracases

Suppose s>t and set Un=sXn+Zn, Vn=t/s Un+1−t/s Wn. The marginal law of Vn is the lower-SNR channel and Xn−Un−Vn is Markov. The chain rule and step 1.1 give h(Un)−h(Vn)=[I(Xn;Un)−I(Xn;Vn)]/ln⁡2=I(Xn;Un∣Vn)/ln⁡2=h(Un∣Vn)−nlog⁡2(πe[1−t/s]): the conditional noise is Zn given t/sZn+1−t/sWn. For a coordinate variance pj, minimizing the quadratic residual variance of Uj given Vj gives (1−t/s)(1+spj)/(1+tpj). Step 1.1 therefore bounds the entropy difference by ∑jlog⁡2((1+spj)/(1+tpj)). This logarithmic ratio has derivative (s−t)/((1+sp)(1+tp)ln⁡2), which is nonnegative and decreasing. Jensen and the average variance bound yield the first claimed inequality. If s=t the two marginal entropies agree; if t=0<s the same construction and computation apply. If s=t=0 both outputs are pure Gaussian noise.

2.2F1F2step 1.1givenalgebra

Let pi,j=Var⁡(Xi,j). The optimal scalar linear estimate of Y1,j from S1,j has residual variance 1+∣h21∣2p2,j+∣h11∣2p1,j/(1+∣h12∣2p1,j): independence of the two user vectors and the noises eliminates all other covariances. Step 1.1 bounds the conditional entropy by the logarithm of this variance times πe. The map x↦x/(1+kx) is increasing and concave on [0,∞) for k≥0, with second derivative −2k/(1+kx)3; hence the residual variance is increasing and concave in the two powers, and its logarithm is also concave and increasing. Jensen and n−1∑jpi,j≤Pi give the first conditional-output bound. Reflection gives the second. This calculation has no division by a channel gain and remains valid when any gain vanishes.

3.1F1F2step 1.1step 2.2givenalgebra∎

The output variances are 1+∣h11∣2p1,j+∣h21∣2p2,j and 1+∣h12∣2p1,j+∣h22∣2p2,j. Applying the coordinate chain rule, [F2], and logarithmic Jensen gives the two unconditioned-output bounds. Given X1n, subtract its contribution from Y2n; independence leaves the linear-estimation problem for h22X2n+Z2n from h21X2n+Z1n. Its coordinate residual variance is 1+∣h22∣2p2,j/(1+∣h21∣2p2,j). The same concavity calculation proves the final conditional bound. Reflection proves its counterpart.

Depends on

Used by

Dependency tree · two levels

22 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources