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Bounded densities with finite second moments have finite differential entropy

Statement

Let f be a Lebesgue probability density on Rd with ∥f∥∞<∞ and ∫∣x∣2f(x) dx<∞. Then ∫f(x)∣ln⁡f(x)∣ dx<∞, so the differential entropy in Differential entropy for real densities is a finite real number.

Facts & Assumptions

Given: A Lebesgue probability density f with finite essential supremum and finite second moment.

[F1]

Differential entropy for real densities: differential entropy is defined by h(f)=−∫fln⁡f in the absolutely integrable case.

Proof

1.1givenalgebra

Let q(x)=(2π)−d/2e−∣x∣2/2 and M=max⁡{1,∥f∥∞}. On {f>1}, fln⁡f≤fln⁡M, so the positive part is integrable. For t≥0, tln⁡(1/t)≤1/e; with t=f/q, this gives fln⁡(q/f)≤q/e. Thus on {f≤1}, −fln⁡f=fln⁡(q/f)−fln⁡q≤q/e+f∣ln⁡q∣. The right side is integrable because q is a probability density and ∣ln⁡q∣ is bounded by a constant plus ∣x∣2/2. Hence the negative part of fln⁡f is integrable.

2.1F1step 1.1algebra∎

Both parts of fln⁡f are integrable by step 1.1. Therefore ∫f∣ln⁡f∣<∞, and [F1] defines a finite differential entropy.

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