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Power bound for real and complex scalar Gaussian channels

Statement

Assume AC. Let X be real or complex with finite second moment, let Z be independent unit-variance Gaussian noise, and let Y=aX+Z. In the real case take Z∼N(0,1) and a∈R; in the complex case take Z∼CN(0,1) with density π−1e−∣z∣2 and a∈C. Put v=E∣X−EX∣2 and κ=1/2 in the real case, κ=1 in the complex case. Then I(X;Y)≤κln⁡(1+∣a∣2v)≤κln⁡(1+∣a∣2E∣X∣2) in nats; division by ln⁡2 gives the corresponding bit formula. Equality in the first inequality holds when X is Gaussian in the real case or circular complex Gaussian in the complex case, including the zero-variance case.

Facts & Assumptions

Given: AC, an input law with finite second moment, independent unit-variance Gaussian noise of the stated type, and the scalar channel Y=aX+Z.

[A1]

The Axiom of Choice: AC is inherited from the real and complex Gaussian entropy bounds and the measure-theoretic information definition.

[F1]

Measure-theoretic mutual information: I(X;Y) is the KL divergence from the joint law to the product of its marginals.

[F2]

Differential entropy for real densities: when Y has a density with absolutely integrable fYln⁡fY, h(Y)=−∫fYln⁡fY.

[F3]

Gaussian maximizes differential entropy at fixed positive-definite covariance: for real Y, h(Y)≤12ln⁡(2πeVar⁡Y).

[F4]

Circular complex Gaussian maximizes differential entropy at fixed second moment: for complex Y, h(Y)≤ln⁡(πeE∣Y−EY∣2).

[F5]

Bounded densities with finite second moments have finite differential entropy: a bounded density with finite second moment has absolutely integrable fln⁡f.

Proof

1.1F2F5givenalgebra

The output density is the convolution fY(y)=∫gZ(y−ax)PX(dx), so 0<fY≤∥gZ∥∞<∞, and Y has finite second moment. By [F5], ∫fY∣ln⁡fY∣<∞, so [F2] defines a finite differential entropy h(Y).

2.1A1F1F2step 1.1algebra

The positive Gaussian noise density makes fY(y)>0. Relative to PX(dx)fY(y)dy, the joint law of (X,Y) has density gZ(y−ax)/fY(y). By [F1], I(X;Y)=∫PX(dx)∫gZ(y−ax)ln⁡gZ(y−ax)fY(y)dy=h(Y)−h(Z). The two logarithmic integrals are finite by step 1.1 and the Gaussian density formula, so this identity involves no subtraction of infinite quantities.

3.1F3F4step 2.1givenalgebra∎

Independence gives Var⁡(Y)=1+∣a∣2v. Apply [F3] and the real Gaussian noise entropy in the real case, or [F4] and h(Z)=ln⁡(πe) in the complex case. Step 2.1 then yields I(X;Y)≤κln⁡(1+∣a∣2v) nats. Since v≤E∣X∣2, division by ln⁡2 gives the corresponding bit bound. For the stated Gaussian inputs, the output is Gaussian of the same real or circular complex type and attains the matching maximum-entropy equality.

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