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Exact strong-interference region for the two-user Gaussian interference channel
Statement
For the real or complex Gaussian interference channel of Real and complex two-user Gaussian interference channels, assume the strong regime Then the capacity region is the set of nonnegative rate pairs satisfying where for real and for complex channels.
Facts & Assumptions
Given: A length- interference code with independent messages, the channel and power constraints of [F1], and the two gain inequalities in the statement.
The Axiom of Choice: AC is inherited through the Gaussian random-coding and scalar-channel information suppliers.
Real and complex two-user Gaussian interference channels: noises are independent unit-variance real or circular complex Gaussian; the input power constraints and SNR/INR conventions are as displayed there.
Random coding achieves the finite-dimensional Gaussian multiple-access region: independent Gaussian codebooks achieve both receivers' multiple-access regions.
Fano bound for finite messages and density observations: a finite message estimated from a density observation with error has conditional entropy at most .
Mutual information tensorizes over a memoryless vector channel: for a memoryless channel and any dependent input vector, vector mutual information is at most the sum of its coordinate mutual informations.
Conditional mutual-information chain rule and data processing for standard-Borel variables: conditional mutual information obeys the chain rule and the data-processing inequality for standard-Borel variables, including finite message side information.
Power bound for real and complex scalar Gaussian channels: for either scalar Gaussian model, nats, with equality for the corresponding Gaussian inputs.
Proof
For the individual bound on , give to receiver 1. Fano gives in nats. For each fixed , is fixed; translating by the known vector is invertible, so [F5] in both directions preserves this conditional mutual information. The shifted channel from is memoryless. The codeword map is deterministic and the channel law depends on only through , so [F5] in both Markov directions gives . Apply [F4] for each and average to bound this by . By [F6], each term is at most nats, where . Jensen's inequality and the power constraint give . Exchanging users gives the stated bound.
First suppose both cross gains are nonzero. Receiver 1 first forms its estimate . On the event , it reconstructs and subtracts , obtaining . Since , it scales this residual by and adds independent Gaussian noise of variance ; for complex channels use circular Gaussian noise. Adding back gives a simulated . For the error analysis, construct the same vector using the true : it then has exactly the law of receiver 2's , and on it equals the receiver's simulation. Hence the joint error is at most . Since the message pair is finite, the randomized decoder has a deterministic MAP decoder with no larger average error. Exchanging users and using gives the symmetric joint decoder at receiver 2.
In the nonzero-cross-gain case of step 1.2, apply the density-observation Fano bound [F3] to the joint decoder at receiver 1. Let and . The deterministic codeword map and channel law give both Markov directions between and with observation , so [F5] yields . The two input vectors are independent because their messages are independent. By [F4], . The output variance at time is at most , because the independent inputs have zero cross covariance after centering. These single-coordinate mutual informations are finite by the power bound and [F6].
For each coordinate put . The channel output depends on the input pair only through , so [F5] in both directions gives . Independence gives ; [F6] therefore bounds this term by nats. Jensen's inequality and the average power constraints yield . The joint decoder at receiver 2 analogously gives . If , then , so by step 1.1; the first sum bound is the individual bound and the second is no tighter because . If , then , so and the second sum bound is the individual bound while the first is no tighter because . Thus both sum bounds hold also when a cross gain vanishes.
Use the same independent Gaussian codebook ensemble at the two receivers. The finite-receiver construction in the proof of [F2] sums the two ensemble-average errors and jointly selects codebooks meeting both deterministic power constraints, so one codebook pair achieves the intersection of the two Gaussian MAC regions. The strong gain inequalities make each unintended-receiver individual constraint at least as large as the corresponding intended-receiver constraint; the two sum constraints are exactly those displayed. Therefore every rate pair strictly inside the claimed region is achievable, and closure removes strictness.
Depends on
- The Axiom of Choice
- Real and complex two-user Gaussian interference channels
- Random coding achieves the finite-dimensional Gaussian multiple-access region
- Fano bound for finite messages and density observations
- Mutual information tensorizes over a memoryless vector channel
- Conditional mutual-information chain rule and data processing for standard-Borel variables
- Power bound for real and complex scalar Gaussian channels
Used by
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Sources
- Abbas El Gamal and Young-Han Kim, Lecture Notes on Network Information Theory, arXiv:1001.3404v4 (standard reference, not scraped)
- M. H. M. Costa and Abbas A. El Gamal, The Capacity Region of the Discrete Memoryless Interference Channel with Strong Interference, IEEE Transactions on Information Theory 33(5), 1987 (standard reference, not scraped)