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Random coding achieves the finite-dimensional Gaussian multiple-access region

Statement

At either receiver of the Gaussian channel in Real and complex two-user Gaussian interference channels, independent Gaussian codebooks with powers P1,P2 achieve every nonnegative rate pair for which each nonempty subset T⊆{1,2} with ∑i∈TRi>0 satisfies ∑i∈TRi<κlog⁡2 ⁣(1+∑i∈T∣ai∣2Pi), where that receiver observes Y=a1X1+a2X2+Z with unit-variance real or complex Gaussian noise and κ=1/2 or 1, respectively. The codebook symbols are centered N(0,Pi) in the real model and circular CN(0,Pi) in the complex model. A subset of zero total rate has no false-message candidates and requires no strict inequality; in particular the zero pair is achieved by singleton message sets. The closure of this achievable set is the usual closed Gaussian multiple-access region.

Facts & Assumptions

Given: The Gaussian channel in [F1], independent Gaussian input laws, and a nonnegative rate pair satisfying the strict inequality for every nonempty subset with positive total rate.

[F1]

Real and complex two-user Gaussian interference channels: the noise is independent standard real Gaussian or unit circular complex Gaussian, with the displayed power convention.

[A1]

The Axiom of Choice: AC is assumed by the Gaussian-law and scalar-channel information suppliers.

[F2]

IID finite-variance weak law: IID square-integrable real random variables obey the weak law, with deviation probability bounded by variance divided by sample size and squared tolerance.

[F3]

Power bound for real and complex scalar Gaussian channels: the mutual information of a scalar additive Gaussian channel is bounded by its variance formula, with equality for the centered Gaussian input specified here.

Proof

1.1A1F1F2givenchoosealgebra

Use the stated full powers Pi in the codebook laws and information densities. Generate Mi=⌈2nRi⌉ codewords independently for each sender, with IID coordinates from its specified centered real or circular complex Gaussian input law. For a nonempty subset S⊆{1,2}, define its one-use information density by ıS(x1,x2;y):=ln⁡w(y∣x1,x2)pY∣XSc(y∣xSc), where w is the Gaussian channel output density and the denominator averages w over the Gaussian input laws of the senders in S. Use the sum of these densities over coordinates as the threshold statistic. For each S with R(S):=∑i∈SRi>0, choose τS so that R(S)ln⁡2<τS<IS, where IS=EıS is in nats. A subset with R(S)=0 has no false-message candidates and needs no threshold. For each tested subset the true statistic is a sum of IID quadratic polynomials in Gaussian variables with finite variance; [F2] makes its threshold test pass with probability tending to one.

2.1F1givenstep 1.1algebra

If a nonempty subset S of positive total rate is wrong, its independently generated candidate codewords are independent of the output conditional on the correct codewords in Sc. By the definition in step 1.1, the exponential of the threshold statistic is the likelihood ratio of the true conditional output density to the density averaged over the candidate input law; its expectation under the false-candidate law is one. The nonnegative likelihood ratio and Markov's inequality therefore bound acceptance by e−nτS. Subsets of zero total rate cannot be wrong because all their message sets are singletons.

3.1step 1.1step 2.1algebra

For each tested subset S, the number of false candidates is at most enR(S)ln⁡2+o(n), so the union bound gives ensemble-average error en→0. For Pi>0, write Ki=nMi and Di=∑t,m(∣Xi,t(m)∣2−Pi); the power constraint is Di≤0. Gaussian moments and independence give EDi=0, vi:=EDi2>0, and EDi4≤15vi2: in the real case the ratio is 3+12/Ki, and in the complex case it is 3+6/Ki. Hölder gives vi≤(E∣Di∣)2/3(EDi4)1/3, hence E∣Di∣≥vi/15. Since E(Di)−=E∣Di∣/2, Cauchy–Schwarz gives Pr⁡{Di<0}≥1/60. If Pi=0, its codebook is identically zero. The two independently generated codebooks therefore meet both power constraints with probability at least 1/3600. Markov bounds the probability of error exceeding en by en; for large n this is less than 1/3600, so there exists a deterministic power-feasible codebook with error at most en→0 (if en=0, error is zero almost surely). For any fixed finite list of receivers satisfying their subset inequalities, apply steps 1.1–2.1 at each receiver to this same input ensemble and replace en by the sum of their average errors; the identical selection then makes every receiver's error vanish.

4.1A1F1F3step 3.1algebra∎

For each nonempty subset S, condition on the other codewords. The remaining signal is a centered real or circular complex Gaussian with variance ∑i∈S∣ai∣2Pi. Its mutual information with the unit-noise output is exactly IS=κln⁡(1+∑i∈S∣ai∣2Pi) nats by [F3] and its Gaussian equality case. Dividing by ln⁡2 gives the rates in bits. Step 3.1 selects deterministic codes from exactly the full-variance ensemble stated above, establishing the strict region under the allowed powers. If both rates are zero, singleton message sets achieve zero error. Taking closure gives the stated closed MAC region, including faces where a zero-rate subset has zero mutual information.

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