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Mutual information tensorizes over a memoryless vector channel

Statement

Assume AC. Let X1,…,Xn and Y1,…,Yn take values in standard-Borel spaces. Let their joint law have an arbitrary input marginal PXn and the memoryless conditional channel law PYn∣Xn(dyn∣xn)=∏i=1nWi(dyi∣xi), where each Wi is a probability kernel. No independence across the input coordinates is assumed. Then, as an inequality in [0,+∞], I(Xn;Yn)≤∑i=1nI(Xi;Yi).

Facts & Assumptions

Given: AC, standard-Borel coordinate spaces, an arbitrary joint input law, and the displayed product conditional channel law.

[A1]

The Axiom of Choice: AC is the choice axiom required by the standard-Borel conditional-law and mutual-information chain-rule suppliers.

[F1]

Standard Borel spaces and Finite products of standard Borel spaces are standard Borel: each coordinate space and each finite product used below is standard Borel.

[F2]

Mutual-information chain rule without subtracting infinities: for standard-Borel random elements, I((Z,X);Y)=I(Z;Y)+I(X;Y∣Z) as an equality of extended nonnegative quantities.

[F3]

Conditional mutual information by a same-marginal product law: conditional mutual information is the KL divergence from the same-marginal conditionally independent product law; it is zero when the conditional joint law equals that product law.

[F4]

Kullback–Leibler divergence is nonnegative: mutual information and conditional mutual information, being KL divergences, are nonnegative.

[F5]

KL is invariant under a measurable bijection: a measurable coordinate permutation preserves KL divergence, so mutual information and conditional mutual information are symmetric in their two unconditioned variables.

[F6]

KL chain rule for standard-Borel disintegrations: when two laws have the same conditioning marginal, their joint KL is the integral of the conditional KLs.

Proof

1.1A1F1F2F5givenalgebra

By [F2], successively adjoining Yi to Yi−1 gives I(Xn;Yn)=I(Yn;Xn)=∑i=1nI(Yi;Xn∣Yi−1)=∑i=1nI(Xn;Yi∣Yi−1). The first equality and the last equality use the coordinate swap in [F5]; the initial term for the empty tuple Y0 is zero. Every term is an extended nonnegative quantity, so no subtraction of infinities is involved.

1.2A1F1F2F3F6givenalgebra

Fix i and put U=Xi, V=X[n]∖{i}, and W=Yi−1. For PW-almost every w, the conditional channel law makes Yi independent of V given U. Apply [F2] to the conditional law of (U,V,Yi) given W=w and use [F3]: I((U,V);Yi∣W=w)=I(U;Yi∣W=w)+I(V;Yi∣U,W=w)=I(U;Yi∣W=w). Integrating this identity over PW gives I(Xn;Yi∣Yi−1)=I(Xi;Yi∣Yi−1) by [F6] and the conditional-KL definition [F3].

1.3A1F2F3F4F5givenalgebra

The product channel law gives I(Yi−1;Yi∣Xi)=0 by [F3]. Expanding I((Xi,Yi−1);Yi) with [F2] first in the order Xi,Yi−1 gives I((Xi,Yi−1);Yi)=I(Xi;Yi). Expanding in the reverse order and using the coordinate-swap invariance [F5] gives I(Xi;Yi)=I(Yi−1;Yi)+I(Xi;Yi∣Yi−1). Because the omitted term I(Yi−1;Yi∣Xi) is zero and I(Yi−1;Yi)≥0 by [F4], this proves I(Xi;Yi∣Yi−1)≤I(Xi;Yi) in the extended nonnegative order.

2.1step 1.1step 1.2step 1.3algebra∎

Sum the coordinate inequalities from step 1.3 and use the chain-rule expansion in step 1.1 together with step 1.2. This gives I(Xn;Yn)≤∑i=1nI(Xi;Yi) for arbitrary dependent input coordinates.

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