Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (deepseek-v4-pro + gpt-5.6-terra)audited 2026-08-26
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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A continuous function holomorphic off a single point is holomorphic

Statement

Let UC be open, let pU, and let f:UC be continuous on U and holomorphic on U{p}. Then f is holomorphic on U, the point p included.

Facts & Assumptions

Given: An open set UC, a point pU, and a function f:UC that is continuous on U and holomorphic on U{p}.

[L1]

If UC is open, pU, and f:UC is continuous and holomorphic on U{p}, then Tf(z)dz=0 for every filled triangle T=Δ[a,b,c] of Filled complex triangles, their oriented three-edge boundary contours, diameter, and perimeter contained in U; the exceptional point may lie outside, inside, or on the boundary of T (Goursat's triangle theorem remains valid for a continuous function holomorphic away from one point).

[L2]

If ΩC is open and f:ΩC is continuous, then f is holomorphic on Ω if and only if Δ[a,b,c]f(z)dz=0 whenever Δ[a,b,c]Ω; repeated or collinear vertices are permitted (Morera's theorem: vanishing triangle integrals characterize holomorphy among continuous functions).

Proof

technique · direct
1.1

The hypotheses of [L1] are exactly the given ones, so Tf(z)dz=0 for every filled triangle TU, whether p lies outside T, inside it, or on its boundary.

givenL1
2.1

The function f is continuous on the open set U and step 1.1 supplies the vanishing triangle integrals demanded by the right-hand side of [L2], so [L2] makes f holomorphic on all of U, including at p.

givenstep 1.1L2

Depends on

Used by

Dependency tree · two levels

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Sources