Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-07
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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Countable intersections of club subsets of omega_1 are club

Statement

Assume ACω. If Cn⊆ω1 is closed and unbounded for every n∈N, then ⋂nCn is closed and unbounded in ω1.

Facts & Assumptions

Proof

technique · diagonal construction
1.1L1

Finite intersections of clubs are club: closedness is immediate, and for two clubs one alternately chooses larger points in them; the supremum of the resulting omega-sequence is below ω1 by [L1] and belongs to both by closedness. Induction handles finitely many.

2.1step 1.1L1

Given α<ω1, recursively choose βk+1∈⋂n≤kCn with βk+1>βk, starting above α; step 1.1 supplies such a point. Let δ=sup⁡kβk<ω1 by [L1]. For each fixed n, the tail (βk)k>n lies in Cn, so closedness gives δ∈Cn. Also δ>α.

3.1step 2.1∎

Thus the intersection is unbounded. It is closed as an arbitrary intersection of closed sets, hence is club.

Depends on

Used by

Dependency tree · two levels

24 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources