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Repeated derivatives along a line expand by the multinomial formula

Statement

Let kNk\in\mathbb N, let URmU\subseteq\mathbb R^m be open, fCk(U)f\in C^k(U), and let IRI\subseteq\mathbb R be an open interval such that a+thUa+th\in U for every tIt\in I. Write ι:NR\iota:\mathbb N\to\mathbb R for the canonical-natural map of The canonical natural ι(n)=n1F\iota(n) = n \cdot 1_F of a field. For g(t)=f(a+th)g(t)=f(a+th) and every 0rk0\le r\le k,

g(r)(t)=α=rι(r!)ι(α!)Dαf(a+th)hα(tI).g^{(r)}(t)=\sum_{|\alpha|=r}\frac{\iota(r!)}{\iota(\alpha!)}D^\alpha f(a+th)h^\alpha\qquad(t\in I).

Facts & Assumptions

Given: The stated open-domain, open-interval, CkC^k, and direction hypotheses.

[L1]

A function with continuous first partial derivatives near a point is totally differentiable there, and the total chain rule then applies to the affine line map ta+tht\mapsto a+th (If all partial derivatives exist on a neighbourhood and are continuous at a point, then the map is totally differentiable there with Jacobian derivative, The chain rule for total derivatives: D(gf)(a)=Dg(f(a))Df(a)D(g\circ f)(a)=Dg(f(a))\circ Df(a)).

[L2]

Ordered mixed derivatives through order kk commute under permutation (Continuous mixed partials of order kk are invariant under permutations).

[L3]

The multi-index conventions α|\alpha|, α!\alpha!, hαh^\alpha, and the canonical derivative DαfD^\alpha f are those of CkC^k maps and multi-index derivative notation in Euclidean space.

Proof

technique · induction
1.1

For r=0r=0 the displayed sum consists of the zero multi-index and equals f(a+th)=g(t)f(a+th)=g(t).

baseL3
1.2

Fix r<kr<k and assume the formula at order rr.

ih
1.3

Each DαfD^\alpha f with α=r|\alpha|=r has continuous first partials, so [L1] differentiates its composition with the affine line. By [L3], we use the canonical multi-index notation for the resulting derivatives. When r=0r=0 the resulting first derivatives are already canonical; when r1r\ge1, [L2] permits the resulting derivatives to be written as Dα+eifD^{\alpha+e_i}f. By [L4], collecting the coefficient of a fixed β\beta with β=r+1|\beta|=r+1 gives

i:βi>0ι(r!)ι((βei)!)=ι(r!)ι(β!)i<mι(βi)=ι((r+1)!)ι(β!).\sum_{i:\,\beta_i>0}\frac{\iota(r!)}{\iota((\beta-e_i)!)}=\frac{\iota(r!)}{\iota(\beta!)}\sum_{i<m}\iota(\beta_i)=\frac{\iota((r+1)!)}{\iota(\beta!)}.

Thus the formula at order r+1r+1 follows. [step 1.2, L1, L2, L3, L4, algebra]

2.1

Steps 1.1--2.1 prove the formula successively for every rkr\le k.

step 1.1step 1.2step 1.3discharge-induction

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 102 results over 28 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

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