Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-05
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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Dimension shift for a cohomological delta functor effaced in the middle

Statement

Let T=(Tn,) be a cohomological delta functor. For a short exact sequence 0AIC0 and an integer n>0, the connecting map n1:Tn1(C)Tn(A) has the following properties:

  1. if Tn1(I)Tn1(C) is the zero map, then n1 is a monomorphism,
  2. if Tn(A)Tn(I) is the zero map, then n1 is an epimorphism,
  3. if both conditions hold, then n1 is an isomorphism.

Facts & Assumptions

Given: A short exact sequence 0AIC0 and an integer n>0.

[L1]

A cohomological delta functor attaches an exact segment Tn1(I)Tn1(C)n1Tn(A)Tn(I) to the given short exact sequence (Cohomological delta functor).

Proof

technique · direct
1.1

By [L1], the kernel of n1 is the image of Tn1(I)Tn1(C). If that map is zero, then ker(n1)=0, so n1 is monic.

L1givenalgebra
1.2

By [L1], the image of n1 is the kernel of Tn(A)Tn(I). If the latter map is zero, this kernel is all of Tn(A), so n1 is epic.

L1givenalgebra
2.1

When both hypotheses hold, steps 1.1 and 1.2 show that n1 is an isomorphism.

step 1.1step 1.2

Depends on

Used by

Dependency tree · two levels

3 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources