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The maximal distributional domain of a geometric Dirac operator is H1
Statement
Assume full AC. Let be closed, Riemannian, and of even dimension . Let be the formally symmetric geometric Dirac operator of Graded Hermitian Clifford modules and geometric Dirac operators, and let have the Lichnerowicz form of Lichnerowicz formula for a geometric Dirac operator. Then its graph norm is equivalent to the norm, smooth sections are a core, and is selfadjoint.
Facts & Assumptions
Given: Full AC, closed compact , the module and operator above, and the compact and Sobolev spaces.
The Lichnerowicz formula says , where is a smooth bounded endomorphism (Lichnerowicz formula for a geometric Dirac operator).
For a formally symmetric Laplace-type bundle operator on compact boundaryless , is an isomorphism for sufficiently large , its inverse maps and is selfadjoint, and smooth data are preserved (Compact Laplace-type bundle operators: regularity and shifted parametrices).
has a smooth finite-dimensional kernel, closed range, and a Green inverse; the exact domain and higher regularity are as in Compact Laplace-type operators: smooth kernel, closed range and Green inverse.
The geometric Dirac operator is globally defined and formally symmetric on closed under Countable Choice (The geometric Dirac operator is globally well defined and formally symmetric).
Full AC supplies the choice assumptions of [F2]–[F4] (The Axiom of Choice).
Proof
Given: The hypotheses in the Statement.
For smooth , formal symmetry [F4] and integration of [F1] against give . Since is bounded and the connection Sobolev norm is equivalent to a finite-chart norm, this gives . Smooth density extends the estimate to , while the first-order local formula gives . Thus the graph norm is equivalent to , and smooth sections are dense in that graph norm.
Let from [F2]. It maps , so is bounded. On smooth , : both solve because commutes with on smooth sections and the solution is unique. Density extends the symmetry identity to .
Suppose and distributionally. Then distributionally. Test against for smooth : formal symmetry gives , using step 1.2 and selfadjointness of . Hence as distributions. The first term is in by the bounded map , and the second is in by [F2]; therefore . Conversely every section has by the first-order local formula, so the maximal distributional domain equals .
The closure of smooth has domain by step 1.1, so its closure is contained in the maximal distributional operator. If , then the distribution equals the vector by the definition of adjoint testing against smooth sections. Step 2.1 gives , and formal symmetry plus density shows . Thus ; the closure is selfadjoint. No compact-resolvent theorem for a general first-order operator is assumed. Full AC supplies the choice assumptions of [F2]–[F4] as recorded in [A1].
Depends on
- Lichnerowicz formula for a geometric Dirac operator
- Second-order Laplace-type operators on metric vector bundles
- Compact Laplace-type bundle operators: regularity and shifted parametrices
- Compact Laplace-type operators: smooth kernel, closed range and Green inverse
- The Axiom of Choice
- Graded Hermitian Clifford modules and geometric Dirac operators
- The geometric Dirac operator is globally well defined and formally symmetric
Used by
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Sources
- Liviu I. Nicolaescu, Notes on the Atiyah–Singer Index Theorem, revision 15 November 2013 (standard reference, not scraped)
- Konstantin Wernli, Lecture Notes on Spin Geometry (2019) (standard reference, not scraped)