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LemmaStatement: AI-adaptedProof: AI-adaptedPipeline-generatedjudge pass (gpt-6.1-sol)
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Disjoint unions of framed cobordisms

Statement

Assume ACω. Let M be a closed smooth manifold and k≥0. Let (WN,εN,ΨN) and (WL,εL,ΨL) be framed codimension-k cobordisms in M×I, from (N0,φ0) to (N1,φ1) and from (L0,ψ0) to (L1,ψ1), respectively. If their images are disjoint, then their union, with the combined framing and collar width min⁡(εN,εL), is a framed cobordism from (N0⊔L0,φ0⊔ψ0) to (N1⊔L1,φ1⊔ψ1).

Disjoint endpoint sets alone do not assert disjointness of the cobordisms. This lemma does not assert that arbitrary embedded framed cobordism classes in a fixed M form a monoid. For finite disjoint sets of framed points, cardinality modulo two is additive, and, when M is oriented, the sum of framing signs is additive.

Facts & Assumptions

Given: Two framed cobordisms as above with WN∩WL=∅.

[F1]

A framed cobordism is a compact neat embedded submanifold with literal product ends of width 0<ε<1/2 and a normal-quotient framing equal to the specified endpoint framing throughout each collar (Framed cobordism of framed submanifolds, Framings of a normal bundle, Neat submanifolds of a manifold with boundary).

Proof

technique · direct
1.1F1F2given

Each of WN,WL is closed by compactness and the Hausdorff property. Thus every point of either has an ambient neighbourhood missing the other. On that neighbourhood W=WN∪WL is exactly the corresponding neat embedded submanifold. Therefore W is a compact neat embedded submanifold, with boundary (N0⊔L0)×{0}⊔(N1⊔L1)×{1}. The normal quotient restricts on each open-and-closed piece to its original normal quotient.

2.1F1step 1.1algebra∎

Set ε=min⁡(εN,εL)∈(0,1/2). The product ends of the two pieces give product ends of W with this width. Their framings paste smoothly on its disjoint open-and-closed pieces and restrict to the combined endpoint framings throughout those collars. Hence (W,ε,ΨN⊔ΨL) is the asserted framed cobordism. For disjoint finite sets, summing one per point, or the orientation sign per point, splits into the sums over the two sets; reducing cardinalities modulo two gives parity additivity. This includes either set being empty and rank-zero cobordisms.

Depends on

Used by

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Dependency tree · two levels

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Sources