How statement and proof provenance work
The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.
- Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
- AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
- AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.
These labels describe origin, not correctness: citations and verification chips remain separate evidence.
E overlap classes form an anticonnected partition
Statement
The relation on the overlap support is an equivalence relation. Its classes partition ; every induced in lies within one class. Each class is nonempty and anticonnected. If , there are no classes.
Facts & Assumptions
E overlap chains inside one comb block supplies the following definition: Fix a block of a finite graph comb (def-comb-in-a-graph). Let consist of all six-vertex subsets of inducing the graph in def-e-graph-and-co-e-graph. Put and . For , define if there exist and vertices in such that each consecutive pair is contained in some . A zero-length chain is allowed. If is empty then and the relation are empty. We call this the overlap chain relation.
Anticonnected graphs and anticonnected components supplies the following definition: A graph is anticonnected, or co-connected, when its complement is connected (def-connected-graph-and-connected-component, def-graph-isomorphism-and-complement). An anticonnected component, or anticomponent, of is a vertex set that is the vertex set of a connected component of . Equivalently, is anticonnected and is inclusion-maximal with that property (def-subgraph-induced-subgraph-and-spanning-subgraph). Under the library convention, the null graph is not anticonnected, while a one-vertex graph is anticonnected.
The -graph and co- supplies the following definition: The -graph is the graph on vertices with edge set Thus is a five-vertex path and is a leaf attached to its middle vertex . The co- graph is the complement of this graph.
Proof
Given: The graph, vertices, sets and hypotheses in the statement.
Length zero gives reflexivity, reversal gives symmetry, and concatenating two finite chains gives transitivity. These assertions also hold on the empty support. Classes cover because each vertex relates to itself; classes meeting at a vertex are equal by symmetry and transitivity.
Any two vertices of one induced have a length-one chain, so that copy lies in one class. In the complement of , is adjacent to and reaches through . Thus the complement is connected.
For two vertices of a class, take a defining chain. Each consecutive pair can be joined in the complement of its witnessing ; all vertices of that copy belong to the class. Concatenation gives a complement walk within the class, from which deleting closed portions gives a path. For an identical pair the length-zero path suffices. The class is nonempty and hence anticonnected.
Depends on
Used by
Cited to discharge well-definedness by E overlap chains inside one comb block.
Dependency tree · two levels
7 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Huang–Ju–Zhou, Erdős–Hajnal beyond the five-vertex path, §6.2, Lemma 6.5, overlap classes (standard reference, not scraped)
- Diestel, Graph Theory, Chapter 1, §§1.1 and 1.4 (foundations) (standard reference, not scraped)