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Comb Structure in co-Bird-Free Graphs
1 · Prerequisites
- Blockades, Combs and Pattern Graphs
- Construction of the Natural Numbers
- Construction of the Real Numbers via Cauchy Sequences
- Construction of the Real Numbers via Dedekind Cuts
- Countability and Uncountability
- Finite Counting, Factorials and Binomial Coefficients
- Foundations of the Real Numbers for Analysis
- Graphs, Walks and Connectivity
- Induced Subgraphs and Hereditary Graph Classes
- Leaf Reducibility and Wonderful Families
- Quotient Blockades and Mixing Relations
- Regular Pairs and Induced Counting
- Relations, Functions, and Quotients
- Roots, Rational Powers, and Classical Inequalities
- Small-Graph Erdős-Hajnal Consequences
- Sparse Restricted Subgraphs and the Rödl–Nikiforov Theorems
- The ZFC Axioms and the Basic Set Constructions
2 · Summary
Two small induced configurations force a vertex selected by a complete nonadjacent pair to be pure on every induced E. Explicit adjacency proofs isolate the terminal-edge cases and provide the local obstruction needed for the structural argument.
Inside each comb block, overlapping E copies form anticonnected classes. Repeated mixed-block quotients preserve external purity and end in a pure blockade with an E-free pattern. The construction includes the empty-overlap case by selecting a singleton; it assumes the additional vertex complete to the comb blocks and anticomplete to the teeth.
3 · Logical flowchart
4 · Definitions, theorems and proofs
The edge-plus-isolate co-Bird obstruction
Statement
Let be a finite simple co-Bird-free graph. Let be distinct vertices outside the indicated induced subgraph, with , and , and with complete to that subgraph. If induces just the edge , then cannot be mixed on and nonadjacent to .
Facts & Assumptions
The Bird graph and co-Bird supplies the following definition: The Bird graph is the graph on vertices with edge set So spans the bull, and is a new leaf attached to the horn vertex . The co-Bird graph is the complement of the Bird graph.
Edges between disjoint vertex sets; complete, anticomplete, pure and mixed pairs supplies the following definition: Let be a finite simple graph and let be disjoint. An edge between and is an edge with and . The pair is: - complete when every is adjacent to every ; - anticomplete when no is adjacent to any ; - pure when it is complete or anticomplete; and - mixed when it is neither complete nor anticomplete. Adjacency is the symmetric edge relation of (def-finite-simple-graph, def-graph-adjacency-incidence-neighbourhood-and-degree). If or , the pair is both complete and anticomplete, hence pure and not mixed.
-free and -free graphs under the induced-subgraph convention supplies the following definition: For finite graphs and , the graph is -free when has no induced copy of (def-induced-embedding-and-induced-copy). Equivalently, (def-induced-copy-number). For a family of finite graphs, a finite graph is -free when it is -free for every . Throughout this page, “free” always refers to induced subgraphs. It does not merely prohibit ordinary subgraph copies.
Proof
Given: The graph, vertices, sets and hypotheses in the statement.
If the forbidden pattern holds, exchange if needed so that is an edge and are nonedges. This exhausts the two meanings of mixed on the edge.
On the six distinct vertices the edges are exactly . The other six pairs are .
The bijection sends those six nonedges to , exactly the Bird edges. It therefore sends edges to co-Bird edges as well. This induced co-Bird contradicts the forbidden-induced-copy hypothesis.
The path-plus-isolate co-Bird obstruction
Statement
Let be a finite simple co-Bird-free graph. Let be distinct vertices outside the indicated induced subgraph, with , and , and with complete to that subgraph. If induces the path and isolated vertex , then cannot be adjacent to and two consecutive vertices of the path and nonadjacent to the remaining endpoint.
Facts & Assumptions
The Bird graph and co-Bird supplies the following definition: The Bird graph is the graph on vertices with edge set So spans the bull, and is a new leaf attached to the horn vertex . The co-Bird graph is the complement of the Bird graph.
Edges between disjoint vertex sets; complete, anticomplete, pure and mixed pairs supplies the following definition: Let be a finite simple graph and let be disjoint. An edge between and is an edge with and . The pair is: - complete when every is adjacent to every ; - anticomplete when no is adjacent to any ; - pure when it is complete or anticomplete; and - mixed when it is neither complete nor anticomplete. Adjacency is the symmetric edge relation of (def-finite-simple-graph, def-graph-adjacency-incidence-neighbourhood-and-degree). If or , the pair is both complete and anticomplete, hence pure and not mixed.
-free and -free graphs under the induced-subgraph convention supplies the following definition: For finite graphs and , the graph is -free when has no induced copy of (def-induced-embedding-and-induced-copy). Equivalently, (def-induced-copy-number). For a family of finite graphs, a finite graph is -free when it is -free for every . Throughout this page, “free” always refers to induced subgraphs. It does not merely prohibit ordinary subgraph copies.
Proof
Given: The graph, vertices, sets and hypotheses in the statement.
Reverse the path if necessary to write the prohibited neighbourhood as . Completeness of and the prescribed path give exactly the edges on .
The six remaining pairs are . Under they map to .
These are exactly the six Bird edges; the other nine pairs are therefore exactly co-Bird edges. The induced copy is forbidden.
A mixed vertex on E is pure on both terminal edges
Statement
Let be a finite simple co-Bird-free graph. Let be distinct vertices outside the indicated induced subgraph, with , and , and with complete to that subgraph. Let induce , with edges exactly . If is mixed on , it is nevertheless pure to both terminal edges and .
Facts & Assumptions
The edge-plus-isolate co-Bird obstruction supplies the following statement: Let be a finite simple co-Bird-free graph. Let be distinct vertices outside the indicated induced subgraph, with , and , and with complete to that subgraph. If induces just the edge , then cannot be mixed on and nonadjacent to .
The path-plus-isolate co-Bird obstruction supplies the following statement: Let be a finite simple co-Bird-free graph. Let be distinct vertices outside the indicated induced subgraph, with , and , and with complete to that subgraph. If induces the path and isolated vertex , then cannot be adjacent to and two consecutive vertices of the path and nonadjacent to the remaining endpoint.
The -graph and co- supplies the following definition: The -graph is the graph on vertices with edge set Thus is a five-vertex path and is a leaf attached to its middle vertex . The co- graph is the complement of this graph.
Proof
Given: The graph, vertices, sets and hypotheses in the statement.
Use the exact five-edge description of . Suppose mixes on . Each of is isolated from this edge; the edge-plus-isolate obstruction forces all three to be neighbours of .
If is present and absent, then must be present: otherwise the path with isolate has precisely the prohibited neighbourhood. Now the path with isolate has that same prohibited pattern, a contradiction.
If is present and absent, the edge with isolate forces to be present. The path with isolate then violates the path-plus-isolate obstruction.
The two possibilities exhaust mixing on . Reflection fixing preserves all five edges and the external hypotheses, and proves the same conclusion for .
Complete nonedge pairs force purity on induced E graphs
Statement
Let be a finite simple co-Bird-free graph. Let be distinct vertices outside the indicated induced subgraph, with , and , and with complete to that subgraph. Let induce , with edges exactly . Then is pure to . In particular, in an -comb with an outside vertex complete to all blocks and anticomplete to all teeth, each , , is pure to every induced in .
Facts & Assumptions
A mixed vertex on E is pure on both terminal edges supplies the following statement: Let be a finite simple co-Bird-free graph. Let be distinct vertices outside the indicated induced subgraph, with , and , and with complete to that subgraph. Let induce , with edges exactly . If is mixed on , it is nevertheless pure to both terminal edges and .
The edge-plus-isolate co-Bird obstruction supplies the following statement: Let be a finite simple co-Bird-free graph. Let be distinct vertices outside the indicated induced subgraph, with , and , and with complete to that subgraph. If induces just the edge , then cannot be mixed on and nonadjacent to .
The path-plus-isolate co-Bird obstruction supplies the following statement: Let be a finite simple co-Bird-free graph. Let be distinct vertices outside the indicated induced subgraph, with , and , and with complete to that subgraph. If induces the path and isolated vertex , then cannot be adjacent to and two consecutive vertices of the path and nonadjacent to the remaining endpoint.
The -graph and co- supplies the following definition: The -graph is the graph on vertices with edge set Thus is a five-vertex path and is a leaf attached to its middle vertex . The co- graph is the complement of this graph.
Combs in a graph supplies the following definition: Let with , and let . An -comb in a graph is a sequence of pairs satisfying the conditions below. Here a vertex is complete to (respectively, anticomplete to) a set when the pair is complete (respectively, anticomplete) in the sense of def-edges-between-sets-and-pure-mixed-pairs. 1. is an -blockade; 2. the vertices are distinct; 3. the set is disjoint from every block ; and 4. for every , the vertex is complete to ; and 5. for all distinct , the vertex is anticomplete to . The vertices are the teeth of the comb.
Proof
Given: The graph, vertices, sets and hypotheses in the statement.
Write using the five-edge definition. If is complete to but misses , the path and isolate violate the second obstruction. If is anticomplete to but sees , the edge and isolate violate the first. Thus purity on implies purity on .
It remains to exclude mixing on . By terminal-edge purity, the adjacency values on agree and those on agree.
If both terminal pairs are complete to , mixing on forces absent. The path and isolate violate the second obstruction. If both are anticomplete, mixing forces present, and the edge with isolate violates the first.
In the remaining case reflect the path so sees and misses . The edge with isolate forces present. The path with isolate forces absent. But then the edge with isolate violates the first obstruction. This exhausts the possibilities and proves purity on .
For the comb assertion substitute . These are distinct nonadjacent vertices outside , both complete to it; is outside and both teeth and is adjacent to but not to . All hypotheses of the proved assertion hold.
E overlap chains inside one comb block
Definition
Fix a block of a finite graph comb (Combs in a graph). Let consist of all six-vertex subsets of inducing the graph in The -graph and co-. Put and . For , define if there exist and vertices in such that each consecutive pair is contained in some . A zero-length chain is allowed. If is empty then and the relation are empty. We call this the overlap chain relation.
Throughout this definition, “the graph in The -graph and co-” means the -graph defined there, not the co- graph.
E overlap classes form an anticonnected partition
Statement
The relation on the overlap support is an equivalence relation. Its classes partition ; every induced in lies within one class. Each class is nonempty and anticonnected. If , there are no classes.
Facts & Assumptions
E overlap chains inside one comb block supplies the following definition: Fix a block of a finite graph comb (def-comb-in-a-graph). Let consist of all six-vertex subsets of inducing the graph in def-e-graph-and-co-e-graph. Put and . For , define if there exist and vertices in such that each consecutive pair is contained in some . A zero-length chain is allowed. If is empty then and the relation are empty. We call this the overlap chain relation.
Anticonnected graphs and anticonnected components supplies the following definition: A graph is anticonnected, or co-connected, when its complement is connected (def-connected-graph-and-connected-component, def-graph-isomorphism-and-complement). An anticonnected component, or anticomponent, of is a vertex set that is the vertex set of a connected component of . Equivalently, is anticonnected and is inclusion-maximal with that property (def-subgraph-induced-subgraph-and-spanning-subgraph). Under the library convention, the null graph is not anticonnected, while a one-vertex graph is anticonnected.
The -graph and co- supplies the following definition: The -graph is the graph on vertices with edge set Thus is a five-vertex path and is a leaf attached to its middle vertex . The co- graph is the complement of this graph.
Proof
Given: The graph, vertices, sets and hypotheses in the statement.
Length zero gives reflexivity, reversal gives symmetry, and concatenating two finite chains gives transitivity. These assertions also hold on the empty support. Classes cover because each vertex relates to itself; classes meeting at a vertex are equal by symmetry and transitivity.
Any two vertices of one induced have a length-one chain, so that copy lies in one class. In the complement of , is adjacent to and reaches through . Thus the complement is connected.
For two vertices of a class, take a defining chain. Each consecutive pair can be joined in the complement of its witnessing ; all vertices of that copy belong to the class. Concatenation gives a complement walk within the class, from which deleting closed portions gives a path. For an identical pair the length-zero path suffices. The class is nonempty and hence anticonnected.
Purity propagates through E overlap chains
Statement
Fix a comb block and an overlap class . If is pure to every induced contained in , then is pure to . In particular, any pure to every induced in is pure to every overlap class.
Facts & Assumptions
E overlap chains inside one comb block supplies the following definition: Fix a block of a finite graph comb (def-comb-in-a-graph). Let consist of all six-vertex subsets of inducing the graph in def-e-graph-and-co-e-graph. Put and . For , define if there exist and vertices in such that each consecutive pair is contained in some . A zero-length chain is allowed. If is empty then and the relation are empty. We call this the overlap chain relation.
Edges between disjoint vertex sets; complete, anticomplete, pure and mixed pairs supplies the following definition: Let be a finite simple graph and let be disjoint. An edge between and is an edge with and . The pair is: - complete when every is adjacent to every ; - anticomplete when no is adjacent to any ; - pure when it is complete or anticomplete; and - mixed when it is neither complete nor anticomplete. Adjacency is the symmetric edge relation of (def-finite-simple-graph, def-graph-adjacency-incidence-neighbourhood-and-degree). If or , the pair is both complete and anticomplete, hence pure and not mixed.
Proof
Given: The graph, vertices, sets and hypotheses in the statement.
Every induced meeting lies in , because any two of its vertices have a length-one overlap chain. On each such six-vertex copy, purity means that all six adjacency values to are equal. If two copies share a vertex, their values coincide at that vertex and therefore agree everywhere.
For any two vertices of a class choose a defining finite chain. Each consecutive pair has equal adjacency to because it lies in a common copy. Equality propagates along the chain, including a zero-length chain. Thus every vertex in the class has the same adjacency value. This is exactly purity. If there are no classes the assertion is vacuous.
The E overlap blockade and mixed quotient sequence
Definition
Fix a comb block with nonempty overlap support . By E overlap classes form an anticonnected partition, its overlap classes are nonempty anticonnected sets partitioning . Fix an enumeration of the finite set , and order the classes by their least enumerated vertex to obtain . Define recursively for , using The quotient blockade obtained from mixed-block reachability and its least-member ordering. Thus one replaces each mixed-reachability class of blocks by its union. This construction is used only when .
E overlap quotients terminate at a pure blockade
Statement
For nonempty overlap support, put . Every stage partitions the same support into nonempty anticonnected blocks and coarsens . There is a least for which is pure, with . At most strict transitions occur, and all stages from onward are identical.
Facts & Assumptions
The E overlap blockade and mixed quotient sequence supplies the following definition: Fix a comb block with nonempty overlap support . By lem-e-overlap-classes-form-an-anticonnected-partition, its overlap classes are nonempty anticonnected sets partitioning . Fix an enumeration of the finite set , and order the classes by their least enumerated vertex to obtain . Define recursively for , using def-quotient-blockade-by-mixed-block-reachability and its least-member ordering. Thus one replaces each mixed-reachability class of blocks by its union. This construction is used only when .
A quotient block of connected or anticonnected blocks is again connected or anticonnected supplies the following statement: Let be a blockade and let be a block of the quotient blockade . 1. If every block of contained in induces a connected subgraph, then is connected. 2. If every block of contained in induces an anticonnected subgraph, then is anticonnected.
The well-ordering principle supplies the following statement: Every nonempty subset has a least element: there is with for all .
Proof
Given: The graph, vertices, sets and hypotheses in the statement.
The initial classes have the asserted properties by the construction. Every quotient is a partition of the same union into unions of old blocks, so coarsening and nonemptiness persist at every stage. The anticonnected clause of the quotient preservation lemma, applied successively, preserves anticonnectedness.
If a stage has a mixed pair, those two blocks belong to the same reachability class, so the next stage has strictly fewer blocks. If it has no mixed pair, every reachability class is a singleton, so the next ordered blockade is identical. Conversely an identical stage cannot have a mixed pair.
The positive integer block count begins at ; after strict decreases it is at most one, when no mixed pair exists. Thus a pure stage exists among . The well-ordering principle gives a least such , and the preceding fixed-stage argument makes all later stages equal. This also covers and zero strict transitions.
A separated anticonnected block pair forbids mixing in one direction
Statement
Let be finite simple and co-Bird-free. Let be disjoint nonempty vertex sets, with anticonnected. Suppose distinct satisfy , both are complete to , , , and is complete to and anticomplete to . Then no vertex of is mixed on .
Facts & Assumptions
The edge-plus-isolate co-Bird obstruction supplies the following statement: Let be a finite simple co-Bird-free graph. Let be distinct vertices outside the indicated induced subgraph, with , and , and with complete to that subgraph. If induces just the edge , then cannot be mixed on and nonadjacent to .
A vertex mixed on an anticonnected set yields opposite adjacency on a nonedge supplies the following statement: Let be a finite graph, let be anticonnected, and let be mixed on . Then there exist distinct vertices such that
Edges between disjoint vertex sets; complete, anticomplete, pure and mixed pairs supplies the following definition: Let be a finite simple graph and let be disjoint. An edge between and is an edge with and . The pair is: - complete when every is adjacent to every ; - anticomplete when no is adjacent to any ; - pure when it is complete or anticomplete; and - mixed when it is neither complete nor anticomplete. Adjacency is the symmetric edge relation of (def-finite-simple-graph, def-graph-adjacency-incidence-neighbourhood-and-degree). If or , the pair is both complete and anticomplete, hence pure and not mixed.
Proof
Given: The graph, vertices, sets and hypotheses in the statement.
If mixes on , the anticonnected witness lemma gives distinct with absent, present and absent. Thus these three vertices induce exactly an edge and an isolate.
The vertices are outside this triple and complete to it. The outside vertex sees the edge endpoint and misses the other endpoint and isolate . This violates the edge-plus-isolate obstruction. Hence such a cannot exist.
External purity survives every E overlap quotient
Statement
Let be an -comb in a finite simple co-Bird-free graph , and let be outside all teeth and blocks, complete to every and anticomplete to every tooth. Fix with nonempty overlap support. For every , every block of and every vertex , the vertex is pure to .
Facts & Assumptions
Complete nonedge pairs force purity on induced E graphs supplies the following statement: Let be a finite simple co-Bird-free graph. Let be distinct vertices outside the indicated induced subgraph, with , and , and with complete to that subgraph. Let induce , with edges exactly . Then is pure to . In particular, in an -comb with an outside vertex complete to all blocks and anticomplete to all teeth, each , , is pure to every induced in .
Purity propagates through E overlap chains supplies the following statement: Fix a comb block and an overlap class . If is pure to every induced contained in , then is pure to . In particular, any pure to every induced in is pure to every overlap class.
The E overlap blockade and mixed quotient sequence supplies the following definition: Fix a comb block with nonempty overlap support . By lem-e-overlap-classes-form-an-anticonnected-partition, its overlap classes are nonempty anticonnected sets partitioning . Fix an enumeration of the finite set , and order the classes by their least enumerated vertex to obtain . Define recursively for , using def-quotient-blockade-by-mixed-block-reachability and its least-member ordering. Thus one replaces each mixed-reachability class of blocks by its union. This construction is used only when .
E overlap quotients terminate at a pure blockade supplies the following statement: For nonempty overlap support, put . Every stage partitions the same support into nonempty anticonnected blocks and coarsens . There is a least for which is pure, with . At most strict transitions occur, and all stages from onward are identical.
A separated anticonnected block pair forbids mixing in one direction supplies the following statement: Let be finite simple and co-Bird-free. Let be disjoint nonempty vertex sets, with anticonnected. Suppose distinct satisfy , both are complete to , , , and is complete to and anticomplete to . Then no vertex of is mixed on .
A vertex mixed on a quotient block but pure on each member block yields two mixed member blocks with opposite adjacency supplies the following statement: Let be a block of the quotient blockade , and let be a vertex. Suppose that is mixed on but is pure to every original block of contained in . Then there are two original blocks of , both contained in , such that 1. and are mixed; and 2. is complete to and anticomplete to .
A quotient-level mixed-block witness descends to two mixed member blocks supplies the following statement: Let be a blockade in a graph , and suppose that every block of is connected or every block is anticonnected. Let be distinct mixed blocks of the quotient blockade . Assume there are vertices such that: 1. and are nonadjacent and both are complete to ; 2. , with complete to and anticomplete to ; and 3. no vertex of is mixed on . Then there are mixed original blocks of , both contained in , and vertices such that: 1. and are nonadjacent and both are complete to ; and 2. , with complete to and anticomplete to .
Combs in a graph supplies the following definition: Let with , and let . An -comb in a graph is a sequence of pairs satisfying the conditions below. Here a vertex is complete to (respectively, anticomplete to) a set when the pair is complete (respectively, anticomplete) in the sense of def-edges-between-sets-and-pure-mixed-pairs. 1. is an -blockade; 2. the vertices are distinct; 3. the set is disjoint from every block ; and 4. for every , the vertex is complete to ; and 5. for all distinct , the vertex is anticomplete to . The vertices are the teeth of the comb.
Proof
Given: The graph, vertices, sets and hypotheses in the statement.
All stages consist of nonempty anticonnected subsets of and are successive mixed quotients. Fix in another comb block. The comb and special vertex give , , , with complete to .
At stage one, the induced- purity lemma makes pure to every in , and overlap propagation makes it pure to every class. If there is no vertex in another block the whole assertion is vacuous.
Assume purity through stage , where , and suppose mixes on a block of stage . It is pure to all member blocks by the induction assumption. The opposite-member-block witness gives mixed blocks of stage inside , with complete to and anticomplete to . Together with these form a separated witness: distinct outside vertices, absent, complete to both blocks, present and absent, and opposite adjacency to the blocks.
Consider such a separated witness on any level . Its second block is anticonnected, so the no-forward-mixing lemma says that no vertex of mixes on . Apply the descending-witness lemma to : every original block is anticonnected, the two blocks are mixed blocks of its quotient, and all outside adjacency hypotheses hold. It gives mixed blocks of level and new outside vertices satisfying exactly the same separated-witness conditions. The outside vertices are distinct: also follows from their completeness to a nonempty set and the relation ; follows from adjacency, and from their opposite adjacency on the nonempty second block.
Repeat this descent finitely until level one (or do nothing if ). Write the resulting blocks as and vertices as . Again no vertex of mixes on . Each such vertex is therefore complete or anticomplete to . Since the pair is mixed, both types occur; otherwise the pair itself would be pure. Choose any . It sees every vertex of the first type and none of the second, so it mixes on .
Now are nonadjacent outside vertices both complete to , while sees and misses . For every induced contained in , apply induced- purity with . Thus is pure to every such copy. Every copy meeting the initial overlap class lies wholly in it, and every defining chain between its vertices stays in it. The overlap propagation proof therefore applies within , and makes pure to , a contradiction.
The assumed mixing at stage is impossible. Starting from stage one and repeating this implication proves the assertion for every positive integer stage, including the fixed terminal stages.
The terminal E overlap pattern is E-free
Statement
For a comb block with nonempty overlap support, the pattern graph of its terminal pure quotient blockade is -free.
Facts & Assumptions
E overlap quotients terminate at a pure blockade supplies the following statement: For nonempty overlap support, put . Every stage partitions the same support into nonempty anticonnected blocks and coarsens . There is a least for which is pure, with . At most strict transitions occur, and all stages from onward are identical.
E overlap chains inside one comb block supplies the following definition: Fix a block of a finite graph comb (def-comb-in-a-graph). Let consist of all six-vertex subsets of inducing the graph in def-e-graph-and-co-e-graph. Put and . For , define if there exist and vertices in such that each consecutive pair is contained in some . A zero-length chain is allowed. If is empty then and the relation are empty. We call this the overlap chain relation. Throughout this definition, “the graph in def-e-graph-and-co-e-graph” means the -graph defined there, not the co- graph.
The pattern graph of a pure blockade supplies the following definition: Let be a pure blockade in a graph . Its pattern graph is the graph with vertex set in which and are adjacent exactly when is complete to . Because the blockade is pure, every unordered pair of distinct blocks is either complete or anticomplete, so this graph is well defined. A pattern graph is called -free when it contains no induced four-vertex path.
The -graph and co- supplies the following definition: The -graph is the graph on vertices with edge set Thus is a five-vertex path and is a leaf attached to its middle vertex . The co- graph is the complement of this graph.
The E overlap blockade and mixed quotient sequence supplies the following definition: Fix a comb block with nonempty overlap support . By lem-e-overlap-classes-form-an-anticonnected-partition, its overlap classes are nonempty anticonnected sets partitioning . Fix an enumeration of the finite set , and order the classes by their least enumerated vertex to obtain . Define recursively for , using def-quotient-blockade-by-mixed-block-reachability and its least-member ordering. Thus one replaces each mixed-reachability class of blocks by its union. This construction is used only when .
Proof
Given: The graph, vertices, sets and hypotheses in the statement.
All terminal blocks are nonempty, pairwise pure, and unions of initial overlap classes. Suppose six distinct pattern vertices induce . Choose one vertex in each corresponding block. The six choices are possible because each block is nonempty, and the chosen vertices are distinct because the blocks are disjoint.
By the definition of the pattern, complete block pairs supply edges between the representatives; nonadjacent pattern pairs, being pure and not complete, are anticomplete. Thus all fifteen pairs of representatives have exactly the adjacency of , including its ten nonedges.
These six vertices form an induced inside , so every pair has an overlap chain of length one and they all belong to a single overlap class. That class is one block of , and coarsening places it in a single terminal block, contradicting the six distinct chosen blocks. If the pattern has fewer than six vertices the prohibited selection is already impossible.
A special-vertex co-Bird-free comb admits an E-free structural partition
Statement
Let be an -comb in a finite simple co-Bird-free graph , and let be outside all teeth and blocks, complete to every and anticomplete to every tooth. For every there exist disjoint sets with such that is -free, and has a partition into a nonempty ordered sequence of nonempty sets satisfying: the sequence is a pure blockade, its pattern is -free, and each individual vertex of every other comb block is pure to each . The blocks may additionally be chosen anticonnected.
Facts & Assumptions
E overlap chains inside one comb block supplies the following definition: Fix a block of a finite graph comb (def-comb-in-a-graph). Let consist of all six-vertex subsets of inducing the graph in def-e-graph-and-co-e-graph. Put and . For , define if there exist and vertices in such that each consecutive pair is contained in some . A zero-length chain is allowed. If is empty then and the relation are empty. We call this the overlap chain relation.
E overlap quotients terminate at a pure blockade supplies the following statement: For nonempty overlap support, put . Every stage partitions the same support into nonempty anticonnected blocks and coarsens . There is a least for which is pure, with . At most strict transitions occur, and all stages from onward are identical.
The terminal E overlap pattern is E-free supplies the following statement: For a comb block with nonempty overlap support, the pattern graph of its terminal pure quotient blockade is -free.
External purity survives every E overlap quotient supplies the following statement: Let be an -comb in a finite simple co-Bird-free graph , and let be outside all teeth and blocks, complete to every and anticomplete to every tooth. Fix with nonempty overlap support. For every , every block of and every vertex , the vertex is pure to .
Combs in a graph supplies the following definition: Let with , and let . An -comb in a graph is a sequence of pairs satisfying the conditions below. Here a vertex is complete to (respectively, anticomplete to) a set when the pair is complete (respectively, anticomplete) in the sense of def-edges-between-sets-and-pure-mixed-pairs. 1. is an -blockade; 2. the vertices are distinct; 3. the set is disjoint from every block ; and 4. for every , the vertex is complete to ; and 5. for all distinct , the vertex is anticomplete to . The vertices are the teeth of the comb.
-free and -free graphs under the induced-subgraph convention supplies the following definition: For finite graphs and , the graph is -free when has no induced copy of (def-induced-embedding-and-induced-copy). Equivalently, (def-induced-copy-number). For a family of finite graphs, a finite graph is -free when it is -free for every . Throughout this page, “free” always refers to induced subgraphs. It does not merely prohibit ordinary subgraph copies.
The -graph and co- supplies the following definition: The -graph is the graph on vertices with edge set Thus is a five-vertex path and is a leaf attached to its middle vertex . The co- graph is the complement of this graph.
The Bird graph and co-Bird supplies the following definition: The Bird graph is the graph on vertices with edge set So spans the bull, and is a new leaf attached to the horn vertex . The co-Bird graph is the complement of the Bird graph.
Proof
Given: The graph, vertices, sets and hypotheses in the statement.
The forbidden pattern here is the complement of the six-vertex Bird, and freeness means absence of an induced copy. Fix . The comb definition ensures is nonempty. Use its overlap support and complement .
If is nonempty, set and . An induced in would put all its vertices in the overlap support, contradicting disjointness. Take the terminal quotient as the partition of ; it is a nonempty pure blockade of anticonnected sets.
The terminal pattern is -free. Every vertex of another comb block is pure to every terminal block by external quotient purity, with the same given comb and special vertex. This verifies all claims in the nonempty-support case.
If is empty, there is no induced anywhere in . Choose the first vertex in a fixed finite enumeration of this nonempty block, and set , . Then is -free. The one-block sequence is pure, anticonnected and has a one-vertex pattern, which cannot contain the six-vertex . Any outside vertex is either adjacent or nonadjacent to , so is pure to this block.
The two support cases exhaust every . Use a fixed enumeration of the finite ambient vertex set for all choices and block orderings. When there are no other-block vertices, so that clause is vacuous; is allowed to be empty. The constructions establish the assertion for all blocks.
5 · Examples, counterexamples and false statements
None yet.
Sources
- Huang–Ju–Zhou, Erdős–Hajnal beyond the five-vertex path, §6.2, Claim 6.5.1(1), Figure 9
- Diestel, Graph Theory, Chapter 1, §§1.1 and 1.4 (foundations)
- Huang–Ju–Zhou, Erdős–Hajnal beyond the five-vertex path, §6.2, Claim 6.5.1(2), Figure 9
- Huang–Ju–Zhou, Erdős–Hajnal beyond the five-vertex path, §6.2, Claim 6.5.2, terminal-edge cases
- Huang–Ju–Zhou, Erdős–Hajnal beyond the five-vertex path, §6.2, Claim 6.5.2
- Huang–Ju–Zhou, Erdős–Hajnal beyond the five-vertex path, §6.2, Lemma 6.5, overlap relation
- Huang–Ju–Zhou, Erdős–Hajnal beyond the five-vertex path, §6.2, Lemma 6.5, overlap classes
- Huang–Ju–Zhou, Erdős–Hajnal beyond the five-vertex path, §6.2, Claim 6.5.3, overlap propagation
- Huang–Ju–Zhou, Erdős–Hajnal beyond the five-vertex path, §6.2, Lemma 6.5, quotient construction
- Huang–Ju–Zhou, Erdős–Hajnal beyond the five-vertex path, §6.2, Lemma 6.5, termination
- Huang–Ju–Zhou, Erdős–Hajnal beyond the five-vertex path, §6.2, Claim 6.5.3, nonedge obstruction
- Huang–Ju–Zhou, Erdős–Hajnal beyond the five-vertex path, §6.2, Claim 6.5.3, full descent
- Huang–Ju–Zhou, Erdős–Hajnal beyond the five-vertex path, §6.2, Lemma 6.5(2.2)
- Huang–Ju–Zhou, Erdős–Hajnal beyond the five-vertex path, §6.2, Lemma 6.5