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Complete nonedge pairs force purity on induced E graphs
Statement
Let be a finite simple co-Bird-free graph. Let be distinct vertices outside the indicated induced subgraph, with , and , and with complete to that subgraph. Let induce , with edges exactly . Then is pure to . In particular, in an -comb with an outside vertex complete to all blocks and anticomplete to all teeth, each , , is pure to every induced in .
Facts & Assumptions
A mixed vertex on E is pure on both terminal edges supplies the following statement: Let be a finite simple co-Bird-free graph. Let be distinct vertices outside the indicated induced subgraph, with , and , and with complete to that subgraph. Let induce , with edges exactly . If is mixed on , it is nevertheless pure to both terminal edges and .
The edge-plus-isolate co-Bird obstruction supplies the following statement: Let be a finite simple co-Bird-free graph. Let be distinct vertices outside the indicated induced subgraph, with , and , and with complete to that subgraph. If induces just the edge , then cannot be mixed on and nonadjacent to .
The path-plus-isolate co-Bird obstruction supplies the following statement: Let be a finite simple co-Bird-free graph. Let be distinct vertices outside the indicated induced subgraph, with , and , and with complete to that subgraph. If induces the path and isolated vertex , then cannot be adjacent to and two consecutive vertices of the path and nonadjacent to the remaining endpoint.
The -graph and co- supplies the following definition: The -graph is the graph on vertices with edge set Thus is a five-vertex path and is a leaf attached to its middle vertex . The co- graph is the complement of this graph.
Combs in a graph supplies the following definition: Let with , and let . An -comb in a graph is a sequence of pairs satisfying the conditions below. Here a vertex is complete to (respectively, anticomplete to) a set when the pair is complete (respectively, anticomplete) in the sense of def-edges-between-sets-and-pure-mixed-pairs. 1. is an -blockade; 2. the vertices are distinct; 3. the set is disjoint from every block ; and 4. for every , the vertex is complete to ; and 5. for all distinct , the vertex is anticomplete to . The vertices are the teeth of the comb.
Proof
Given: The graph, vertices, sets and hypotheses in the statement.
Write using the five-edge definition. If is complete to but misses , the path and isolate violate the second obstruction. If is anticomplete to but sees , the edge and isolate violate the first. Thus purity on implies purity on .
It remains to exclude mixing on . By terminal-edge purity, the adjacency values on agree and those on agree.
If both terminal pairs are complete to , mixing on forces absent. The path and isolate violate the second obstruction. If both are anticomplete, mixing forces present, and the edge with isolate violates the first.
In the remaining case reflect the path so sees and misses . The edge with isolate forces present. The path with isolate forces absent. But then the edge with isolate violates the first obstruction. This exhausts the possibilities and proves purity on .
For the comb assertion substitute . These are distinct nonadjacent vertices outside , both complete to it; is outside and both teeth and is adjacent to but not to . All hypotheses of the proved assertion hold.
Depends on
Used by
Dependency tree · two levels
9 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Huang–Ju–Zhou, Erdős–Hajnal beyond the five-vertex path, §6.2, Claim 6.5.2 (standard reference, not scraped)