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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.
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A separated anticonnected block pair forbids mixing in one direction
Statement
Let be finite simple and co-Bird-free. Let be disjoint nonempty vertex sets, with anticonnected. Suppose distinct satisfy , both are complete to , , , and is complete to and anticomplete to . Then no vertex of is mixed on .
Facts & Assumptions
The edge-plus-isolate co-Bird obstruction supplies the following statement: Let be a finite simple co-Bird-free graph. Let be distinct vertices outside the indicated induced subgraph, with , and , and with complete to that subgraph. If induces just the edge , then cannot be mixed on and nonadjacent to .
A vertex mixed on an anticonnected set yields opposite adjacency on a nonedge supplies the following statement: Let be a finite graph, let be anticonnected, and let be mixed on . Then there exist distinct vertices such that
Edges between disjoint vertex sets; complete, anticomplete, pure and mixed pairs supplies the following definition: Let be a finite simple graph and let be disjoint. An edge between and is an edge with and . The pair is: - complete when every is adjacent to every ; - anticomplete when no is adjacent to any ; - pure when it is complete or anticomplete; and - mixed when it is neither complete nor anticomplete. Adjacency is the symmetric edge relation of (def-finite-simple-graph, def-graph-adjacency-incidence-neighbourhood-and-degree). If or , the pair is both complete and anticomplete, hence pure and not mixed.
Proof
Given: The graph, vertices, sets and hypotheses in the statement.
If mixes on , the anticonnected witness lemma gives distinct with absent, present and absent. Thus these three vertices induce exactly an edge and an isolate.
The vertices are outside this triple and complete to it. The outside vertex sees the edge endpoint and misses the other endpoint and isolate . This violates the edge-plus-isolate obstruction. Hence such a cannot exist.
Depends on
Used by
Dependency tree · two levels
8 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Huang–Ju–Zhou, Erdős–Hajnal beyond the five-vertex path, §6.2, Claim 6.5.3, nonedge obstruction (standard reference, not scraped)