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Comb Structure in co-Bird-Free Graphs — Examples

1 · Prerequisites

2 · Summary

3 · Logical flowchart

4 · Definitions, theorems and proofs

None yet.

5 · Examples, counterexamples and false statements

ExampleConstruction: AI-adaptedVerification: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-07Open item page →

The first co-Bird witness by adjacency

Example

On six distinct vertices (x,y,u,a,b,c) take exactly the edges xa,xb,xc,ya,yb,yc,xu,ua,ab. This graph is co-Bird and realizes the edge-plus-isolate obstruction configuration.

Facts & Assumptions

[F1]

The edge-plus-isolate co-Bird obstruction supplies the following statement: Let G be a finite simple co-Bird-free graph. Let x,y,u be distinct vertices outside the indicated induced subgraph, with xyE(G), uxE(G) and uyE(G), and with x,y complete to that subgraph. If H={a,b,c} induces just the edge ab, then u cannot be mixed on {a,b} and nonadjacent to c.

[F2]

The Bird graph and co-Bird supplies the following definition: The Bird graph is the graph on vertices {x1,x2,x3,y,z,w} with edge set {x1x2,x2x3,x1x3,x1y,x2z,yw}. So {x1,x2,x3,y,z} spans the bull, and w is a new leaf attached to the horn vertex y. The co-Bird graph is the complement of the Bird graph.

Verification

Given: The graph, vertices, sets and hypotheses in the example.

1.1

The fifteen unordered pairs split into nine edges xa,xb,xc,ya,yb,yc,xu,ua,ab and six nonedges xy,yu,ub,uc,ac,bc. Under (x,y,u,a,b,c)(w,y,x1,z,x3,x2) the latter become precisely wy,yx1,x1x3,x1x2,zx2,x3x2, the Bird edges. The map is bijective and hence verifies both edges and nonedges of co-Bird.

F2given
2.1

The induced set {a,b,c} has just edge ab, the nonadjacent pair x,y is complete to it, and u sees x,a but misses y,b,c. These are exactly the prohibited data of the first obstruction; the example itself contains co-Bird and therefore does not satisfy that lemma’s freeness assumption.

F1
ExampleConstruction: AI-adaptedVerification: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-07Open item page →

The second co-Bird witness by adjacency

Example

On six distinct vertices (y,u,a,b,c,d) take exactly the edges ya,yb,yc,yd,ub,uc,ud,ab,bc. This graph is co-Bird and is the six-vertex witness for the path-plus-isolate obstruction.

Facts & Assumptions

[F1]

The path-plus-isolate co-Bird obstruction supplies the following statement: Let G be a finite simple co-Bird-free graph. Let x,y,u be distinct vertices outside the indicated induced subgraph, with xyE(G), uxE(G) and uyE(G), and with x,y complete to that subgraph. If H={a,b,c,d} induces the path abc and isolated vertex d, then u cannot be adjacent to d and two consecutive vertices of the path and nonadjacent to the remaining endpoint.

[F2]

The Bird graph and co-Bird supplies the following definition: The Bird graph is the graph on vertices {x1,x2,x3,y,z,w} with edge set {x1x2,x2x3,x1x3,x1y,x2z,yw}. So {x1,x2,x3,y,z} spans the bull, and w is a new leaf attached to the horn vertex y. The co-Bird graph is the complement of the Bird graph.

Verification

Given: The graph, vertices, sets and hypotheses in the example.

1.1

The complement consists exactly of the six pairs yu,ua,ac,ad,bd,cd. The other nine of the fifteen pairs are the stated edges. The bijection (y,u,a,b,c,d)(w,y,x1,z,x3,x2) sends these six pairs to wy,yx1,x1x3,x1x2,zx2,x3x2, precisely the Bird edges, and sends the other pairs to co-Bird edges.

F2given
2.1

Here abc is induced, d is isolated from that path, y is complete to all four vertices and misses u, while u sees exactly b,c,d among them. These are the six vertices of the co-Bird witness underlying the second obstruction. The obstruction's full hypothesis also requires a seventh vertex x: add x adjacent to u,a,b,c,d and nonadjacent to y; the displayed induced co-Bird persists.

F1
ExampleConstruction: AI-adaptedVerification: AI-adaptedjudge pass (gpt-5.6-terra)audited 2026-09-07Open item page →

All E neighbourhood patterns under a complete nonedge pair

Example

Let G be a finite simple co-Bird-free graph. Let x,y,u be distinct vertices outside the indicated induced subgraph, with xyE(G), uxE(G) and uyE(G), and with x,y complete to that subgraph. Let S={p1,p2,p3,p4,p5,q} induce E, with edges exactly p1p2,p2p3,p3p4,p4p5,p3q. The 64 subsets N(u)S, encoded by six adjacency bits, reduce to the empty and full subsets after imposing the two local obstruction tests. The table gives a witness for each of the 62 mixed subsets.

Facts & Assumptions

[F1]

The edge-plus-isolate co-Bird obstruction supplies the following statement: Let G be a finite simple co-Bird-free graph. Let x,y,u be distinct vertices outside the indicated induced subgraph, with xyE(G), uxE(G) and uyE(G), and with x,y complete to that subgraph. If H={a,b,c} induces just the edge ab, then u cannot be mixed on {a,b} and nonadjacent to c.

[F2]

The path-plus-isolate co-Bird obstruction supplies the following statement: Let G be a finite simple co-Bird-free graph. Let x,y,u be distinct vertices outside the indicated induced subgraph, with xyE(G), uxE(G) and uyE(G), and with x,y complete to that subgraph. If H={a,b,c,d} induces the path abc and isolated vertex d, then u cannot be adjacent to d and two consecutive vertices of the path and nonadjacent to the remaining endpoint.

[F3]

Complete nonedge pairs force purity on induced E graphs supplies the following statement: Let G be a finite simple co-Bird-free graph. Let x,y,u be distinct vertices outside the indicated induced subgraph, with xyE(G), uxE(G) and uyE(G), and with x,y complete to that subgraph. Let S={p1,p2,p3,p4,p5,q} induce E, with edges exactly p1p2,p2p3,p3p4,p4p5,p3q. Then u is pure to S. In particular, in an (,w)-comb with an outside vertex v complete to all blocks and anticomplete to all teeth, each uBk, ki, is pure to every induced E in Bi.

[F4]

The E-graph and co-E supplies the following definition: The E-graph is the graph on vertices {p1,p2,p3,p4,p5,q} with edge set {p1p2,p2p3,p3p4,p4p5,p3q}. Thus p1p2p3p4p5 is a five-vertex path and q is a leaf attached to its middle vertex p3. The co-E graph is the complement of this graph.

Verification

Given: The graph, vertices, sets and hypotheses in the example.

1.1

For any row of type I the five-edge list verifies an induced edge-plus-isolate with adjacency bits (1,0,0); type II verifies an induced path-plus-isolate with bits (0,1,1,1). The respective obstruction forbids that row under the common complete-nonedge-pair hypotheses. All witness vertices lie in S, so the required outside vertices remain outside.

F1F2F4
1.2

The symbolic proof of induced-E purity also groups these possibilities exhaustively: constant adjacency on the five-vertex path forces the matching value at q; mixing on either terminal edge is impossible; equal terminal-pair values force the middle value; opposite terminal-pair values give the final contradiction. Consequently every mixed six-bit assignment is excluded without relying on a smoke test. The table supplies one direct witness for each such assignment.

F3
2.1

For mask 0, type I lacks its required neighbour and type II lacks three required neighbours. For mask 63, type I lacks its two required nonneighbours and type II lacks its required nonneighbour. Hence neither local test rejects either constant mask, and exactly these two of the 64 subsets survive the tests. This is a statement about the two tests, not a sufficiency assertion for freeness of an arbitrary ambient graph.

given

Adjacency table

Each mask is m=j=052jϵj in order (p1,p2,p3,p4,p5,q). Type I lists (a,b,c): edge ab, isolate c, adjacency bits (1,0,0). Type II lists (a,b,c,d): path abc, isolate d, bits (0,1,1,1). Thus every row is an explicit prohibited induced configuration, checkable against the five-edge list.

MaskTypeOrdered witness
1I(p1,p2,p4)
2I(p2,p1,p4)
3I(p2,p3,p5)
4I(p3,p2,p5)
5I(p1,p2,p4)
6I(p2,p1,p4)
7I(p3,q,p5)
8I(p4,p3,p1)
9I(p1,p2,p5)
10I(p2,p1,p5)
11I(p2,p3,p5)
12I(p3,p2,p5)
13I(p1,p2,p5)
14I(p2,p1,p5)
15I(p3,q,p5)
16I(p5,p4,p1)
17I(p1,p2,p4)
18I(p2,p1,p4)
19I(p5,p4,q)
20I(p3,p4,p1)
21I(p1,p2,p4)
22I(p2,p1,p4)
23I(p5,p4,q)
24I(p4,p3,p1)
25I(p1,p2,q)
26I(p2,p1,q)
27II(p3,p2,p1,p5)
28I(p3,q,p1)
29I(p1,p2,q)
30I(p2,p1,q)
31II(q,p3,p2,p5)
32I(q,p3,p1)
33I(p1,p2,p4)
34I(p2,p1,p4)
35I(p2,p3,p5)
36I(p3,p2,p5)
37I(p1,p2,p4)
38I(p2,p1,p4)
39II(p4,p3,q,p1)
40I(p4,p3,p1)
41I(p1,p2,p5)
42I(p2,p1,p5)
43I(p2,p3,p5)
44I(p3,p2,p5)
45I(p1,p2,p5)
46I(p2,p1,p5)
47II(p5,p4,p3,p1)
48I(p5,p4,p1)
49I(p1,p2,p4)
50I(p2,p1,p4)
51II(p3,p2,p1,p5)
52I(p3,p4,p1)
53I(p1,p2,p4)
54I(p2,p1,p4)
55II(p4,p3,q,p1)
56I(p4,p3,p1)
57II(p3,p4,p5,p1)
58I(p4,p3,p1)
59II(p3,p2,p1,p5)
60II(p2,p3,q,p5)
61II(p2,p3,q,p5)
62II(p1,p2,p3,p5)
ExampleConstruction: AI-generatedVerification: AI-generatedjudge pass (gpt-5.6-terra)audited 2026-09-07Open item page →

The no-E-copy boundary case of the comb partition

Example

Let V(G)={a,b,v} and E(G)={ab,vb}. The one-tooth (1,1)-comb ((a,{b})) has special vertex v. In the structural partition take X={b}, Y= and the singleton blockade ({b}).

Facts & Assumptions

[F1]

A special-vertex co-Bird-free comb admits an E-free structural partition supplies the following statement: Let ((ak,Bk):k[]) be an (,w)-comb in a finite simple co-Bird-free graph G, and let v be outside all teeth and blocks, complete to every Bk and anticomplete to every tooth. For every i[] there exist disjoint sets Xi,Yi with Bi=XiYi such that G[Yi] is E-free, and Xi has a partition into a nonempty ordered sequence (A1i,,Atii) of nonempty sets satisfying: the sequence is a pure blockade, its pattern is E-free, and each individual vertex of every other comb block is pure to each Aji. The blocks Aji may additionally be chosen anticonnected.

[F2]

Combs in a graph supplies the following definition: Let N with 1, and let w>0. An (,w)-comb in a graph G is a sequence of pairs ((ai,Bi):i[]) satisfying the conditions below. Here a vertex a is complete to (respectively, anticomplete to) a set B when the pair ({a},B) is complete (respectively, anticomplete) in the sense of def-edges-between-sets-and-pure-mixed-pairs. 1. (B1,,B) is an (,w)-blockade; 2. the vertices a1,,a are distinct; 3. the set {a1,,a} is disjoint from every block Bi; and 4. for every i[], the vertex ai is complete to Bi; and 5. for all distinct i,j[], the vertex ai is anticomplete to Bj. The vertices ai are the teeth of the comb.

[F3]

The E-graph and co-E supplies the following definition: The E-graph is the graph on vertices {p1,p2,p3,p4,p5,q} with edge set {p1p2,p2p3,p3p4,p4p5,p3q}. Thus p1p2p3p4p5 is a five-vertex path and q is a leaf attached to its middle vertex p3. The co-E graph is the complement of this graph.

[F4]

The Bird graph and co-Bird supplies the following definition: The Bird graph is the graph on vertices {x1,x2,x3,y,z,w} with edge set {x1x2,x2x3,x1x3,x1y,x2z,yw}. So {x1,x2,x3,y,z} spans the bull, and w is a new leaf attached to the horn vertex y. The co-Bird graph is the complement of the Bird graph.

Verification

Given: The graph, vertices, sets and hypotheses in the example.

1.1

The graph has only three vertices and hence cannot contain the six-vertex co-Bird. The single block is nonempty of size one, its tooth a is outside it and complete to it, and v is outside both and sees b but misses a. There are no distinct-tooth conditions to check.

F4F2given
2.1

The block contains no six-vertex E, so its overlap support is empty. The singleton branch of the structural theorem gives exactly the displayed X,Y. The empty graph on Y and the one-vertex pattern contain no E, the one-block blockade is pure, and the other-block purity condition is vacuous.

F1F3

Sources