Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (deepseek-v4-pro + gpt-5.6-terra)audited 2026-08-16
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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An irregularity witness raises the pair energy by more than ϵ4XY/n2

Statement

Let G have order n>0, let X,YV(G) be nonempty, and suppose that AX, BY witness that (X,Y) is not ϵ-regular. If A={A,XA} and B={B,YB} after empty cells are omitted, then q(A,B)XYn2d(X,Y)2>ϵ4XYn2.

Facts & Assumptions

Given: An irregular pair and witness sets as in the Statement.

[L1]

Such witnesses satisfy AϵX, BϵY, and d(A,B)d(X,Y)>ϵ (ϵ-regular pairs and self-regular vertex sets).

[L2]

Pair energy is the product-size-weighted mean square of the densities of the refined subpairs (The mean-square density, or energy, of a vertex partition).

Proof

technique · direct
1.1

Choose (x,y) uniformly from X×Y, and let Z be the density between the cells of A and B containing x and y. Double-counting gives EZ=d(X,Y), and [L2] identifies XYE(Z2)/n2 with q(A,B).

givenL2algebra
2.1

Therefore the energy gain in the Statement is (XY/n2)Var(Z)=(XY/n2)E((Zd(X,Y))2).

step 1.1algebra
2.2

On the event (x,y)A×B, which has probability AB/(XY)ϵ2 by [L1], the random variable equals d(A,B) and differs from its mean by more than ϵ.

L1step 1.1
3.1

Restricting the nonnegative expectation in step 2.1 to this event gives a strict lower bound ϵ2ϵ2XY/n2, which is the asserted boost.

step 2.1step 2.2algebra

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 6 results over 6 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources