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LemmaStatement: Literature-sourcedProof: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-04
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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The prime field lifts in the equicharacteristic case

Statement

Let (A,m) be an equicharacteristic local ring with residue field k=A/m. Then the prime field of k has a canonical copy inside A, and the residue map identifies that copy with the prime field of k.

Facts & Assumptions

Given: An equicharacteristic local ring (A,m) with residue field k.

[L1]

Every field has a prime subfield, isomorphic either to Q or to Fp according to its characteristic (A field's prime subfield is isomorphic to Q in characteristic zero and to Fp in characteristic p).

[L2]

Equicharacteristic means char(A)=char(k) (Equicharacteristic local rings and coefficient fields).

Proof

technique · compare the two characteristics
1.1

By [L2], the ring A and its residue field k have the same characteristic. If that characteristic is 0, then the unique map ZA kills no nonzero integer, so it extends to an embedding QA. If the characteristic is p>0, then the image of ZA is a copy of Fp inside A.

L1L2givenalgebra
2.1

Reducing these embedded prime fields modulo m gives the prime subfield of k, because A and k have the same characteristic and prime subfields are unique by [L1].

L1step 1.1
3.1

Therefore the prime field of the residue field lifts canonically in the equicharacteristic case.

step 2.1

Depends on

Used by

Dependency tree · two levels

9 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources