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The Euler-twisted Hall product is well-defined

Statement

For a finite-field hereditary Hall category, the basis formula in The Euler-twisted Hall algebra has finite support and defines a Q(ν)-bilinear operation on the direct-sum Hall space.

Facts & Assumptions

Given: The category, ν=q, and the Euler-twisted basis formula.

[F1]

The untwisted coefficient gM,NL is finite and has finite support in [L] for fixed M,N (Untwisted Hall structure constants and products are finite).

[F2]

The twist scalar νχ0(M,N) is a well-defined element of Q(ν) because χ0(M,N) is an integer (The Euler-twisted Hall algebra).

Proof

1.1F1F2given

For fixed M,N, [F1] gives a finite set of isomorphism classes [L] with nonzero Hall coefficient. Multiplication by the single scalar in [F2] does not enlarge that support, so the displayed basis product is a finite linear combination in the direct sum.

2.1step 1.1algebra∎

Every Hall vector has finite support. Bilinearity therefore expands any product of two vectors into a finite sum of the finite basis products in step 1.1, producing an element of the same direct sum.

Depends on

Used by

Cited to discharge well-definedness by The Euler-twisted Hall algebra.

Dependency tree · two levels

6 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources