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Fiber transport gives the Serre local systems
Statement
Let be a Hurewicz fibration, , a commutative unital ring, and . The assignments and are -module local systems on . Thus cohomology uses transport along the reversed path before applying contravariance.
For a commutative square of fibrations with total map over , the fiber maps induce a natural transformation from the homology system of to the pullback of that of , and a natural transformation in the reverse coefficient direction from the pullback of the cohomology system of to that of .
Facts & Assumptions
Given: The fibration, coefficient ring, degree, and, for functoriality, the commutative square in the statement.
Fiber transport and monodromy action proves that the homotopy class of depends only on , that , and that is a fiber-homotopy inverse to .
The singular chain homotopy formula says homotopic maps induce chain-homotopic singular chain maps.
Singular cochain complex with coefficients defines cochains by applying to singular chains, with positive coboundary.
Local systems and pullback identifies the required conclusion with functorial transport on the fundamental groupoid.
Proof
If maps are homotopic, [F2] supplies . Hence they induce the same map in homology. Precomposition with this equality gives on cochains, where ; thus they induce the same map in cohomology as well. A homotopy equivalence therefore induces isomorphisms in both theories.
For homology, path-homotopy invariance and composition follow from [F1] and step 1.1: . Constant paths give identity maps in homology even if the chosen lifting function is not regular, because [F1] makes their transports homotopic to the identity. Reversed paths give inverse maps. This is the covariant groupoid functor required by [F4].
Define cohomology transport along to be . Since , [F1] gives . Contravariance and step 1.1 then give . Constants give identities, and is inverse to . Thus this too is a covariant fundamental-groupoid functor.
In the commutative square, write . For a path , the two maps and are fiber transports over the same base path with the same initial fiber map. The lifting comparison in [F1] gives a vertical homotopy between them. Step 1.1 therefore gives , exactly naturality of .
Apply the same comparison to . Contravariance gives as maps from to . This is naturality of the stalk maps from the pulled-back cohomology system to the source system.
Empty fibers give zero modules, and [F1] makes emptiness constant along each path component; point fibers and obey the same formulas. The zero ring gives zero systems. Disconnected bases are handled componentwise. A universal lifting function is one supplied map, and all subsequent transports and prism homotopies concern specified paths or maps; no family of representatives is selected, so no AC is used.
Depends on
Used by
- An untwisted E2 table misses mapping-torus monodromy Counterexample
Dependency tree · two levels
19 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Davis and Kirk, Lecture Notes in Algebraic Topology, Chapter 5 §3, pp.103–107 (standard reference, not scraped)