Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-generatedPipeline-generatedprecheck pass
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The finite KL generator has the required convex boundary extension

Statement

For f(t)=tlog⁡t on t>0, one has f(1)=0, f is convex on (0,∞), lim⁡t↓0f(t)=0, and lim⁡t→∞f(t)/t=+∞.

Facts & Assumptions

Given: The function f:(0,∞)→R defined by f(t)=tlog⁡t.

[F1]

The natural logarithm as the inverse of the exponential function and Order, continuity, range, and the product, quotient, and reciprocal laws for the natural logarithm: log⁡ is defined on (0,∞), is strictly increasing and onto R, satisfies log⁡1=0, and log⁡(1/t)=−log⁡t.

[F3]

A twice-differentiable function on an open interval is convex if and only if its second derivative is nonnegative and Convex and strictly convex functions on Euclidean convex sets: a twice differentiable function on an open interval is convex when its second derivative is nonnegative there.

[F4]

The logarithm grows more slowly than every positive real power: log⁡s/s→0 as s→+∞.

Proof

1.1F1F2F3givenalgebra

By [F1], f(1)=log⁡1=0. The difference quotient in [F2] gives derivative 1 for the identity function and 0 for a constant function. Applying the product rule and then the logarithm derivative in [F2] yields f′(t)=log⁡t+1 and f′′(t)=1/t>0 for every t>0. Thus [F3] gives convexity on (0,∞).

1.2F1F4givenalgebra

Put s=1/t. As t↓0, s→+∞ and [F1] gives tlog⁡t=−log⁡(s)/s. Its limit is zero by [F4], so lim⁡t↓0f(t)=0.

2.1F1givenchoosealgebra∎

For t>0, f(t)/t=log⁡t. Since log⁡ is increasing and onto R by [F1], for each real M there exists a>0 with log⁡a>M, and every t>a has log⁡t≥log⁡a>M. Thus lim⁡t→∞f(t)/t=+∞.

Depends on

Used by

Dependency tree · two levels

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Sources