Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (deepseek-v4-pro + gpt-5.6-terra)audited 2026-08-21
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Finite measures agreeing on a generating pi-system and on the whole space are equal

Statement

Let P be a pi-system on X and let A=σX(P). If finite measures μ and ν on (X,A) agree on P and satisfy μ(X)=ν(X), then μ=ν on A.

The total-mass equality is separate because this library's pi-system convention does not require XP.

Facts & Assumptions

Given: A pi-system P generating A, and finite measures μ,ν agreeing on P and on X.

[L1]

A pi-system is a nonempty family closed under binary intersections and need not contain X (Pi-systems).

[L2]

If a lambda-system contains a pi-system P, then it contains σX(P) (Dynkin's pi-lambda theorem).

[L3]

Measures are finitely and countably additive (Measures on sigma-algebras) and continuous from below (Continuity from below for measures).

[L4]

For finite measures, the value on a relative difference is obtained by subtracting the smaller-set value (Measure of a set difference when the smaller set has finite measure).

[L5]

The generated sigma-algebra is the intersection of all sigma-algebras containing the generating family (The sigma-algebra generated by a family of sets).

Proof

technique · direct
1.1

Let D:={AA:μ(A)=ν(A)}. Then XD by the total-mass hypothesis and PD by the agreement hypothesis.

givenL1
1.2

If AB lie in D, finiteness and [L4] give μ(BA)=μ(B)μ(A)=ν(B)ν(A)=ν(BA), so BAD.

givenL4algebra
1.3

If AnA and each AnD, continuity from below gives μ(A)=supnμ(An)=supnν(An)=ν(A), so AD.

givenL3
2.1

Steps 1.1, 1.2 and 1.3 show that D is a lambda-system containing P.

step 1.1step 1.2step 1.3
3.1

Dynkin's theorem gives A=σX(P)D, so μ(A)=ν(A) for every AA.

step 2.1L2L5

Depends on

Used by

Dependency tree · two levels

15 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources