Alphabeta Math
LemmaStatement: AI-adaptedProof: AI-adaptedPipeline-generatedjudge pass (gpt-6-luna)
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A finite second moment defines a positive semidefinite covariance matrix

Statement

If X∈Rp is measurable and E∥X∥22<∞, then μ=EX and Σ=E[(X−μ)(X−μ)T] in Covariance matrix of a finite-dimensional random vector are well-defined entrywise, Σ is symmetric positive semidefinite, and tr⁡(Σ)=E∥X−μ∥22.

Facts & Assumptions

Given: A finite-dimensional measurable random vector X with E∥X∥22<∞.

[F1]

Covariance matrix of a finite-dimensional random vector defines the mean coordinatewise and covariance entries by E[(Xj−μj)(Xk−μk)].

[F2]

Expectation of a nonnegative or integrable random variable: finite expectation is defined for integrable real random variables.

Proof

1.1givenF1F2algebra

For each coordinate, ∣Xj∣≤∥X∥2 and ∣x∣≤(1+x2)/2 imply E∣Xj∣<∞, so every μj exists. Also E(Xj−μj)2<∞, since (Xj−μj)2≤2Xj2+2μj2.

2.1step 1.1F1F2algebra

For every pair j,k, 2∣(Xj−μj)(Xk−μk)∣≤(Xj−μj)2+(Xk−μk)2. Thus every covariance entry is integrable; all entries are finite and symmetry follows from commutativity of multiplication.

3.1step 2.1F1F2algebra∎

For a∈Rp, aTΣa=E[(aT(X−μ))2]≥0, so Σ is positive semidefinite. Summing the diagonal entries gives tr⁡(Σ)=∑jE(Xj−μj)2=E∑j(Xj−μj)2=E∥X−μ∥22; the sum is finite.

Depends on

Used by

Cited to discharge well-definedness by Covariance matrix of a finite-dimensional random vector.

Dependency tree · two levels

8 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources