Alphabeta Math
LemmaStatement: AI-adaptedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (gpt-5.6-terra)audited 2026-08-26
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Foata's transformation is a bijection of Sn

Statement

For every nN, Foata's transformation Φ is a bijection SnSn.

Facts & Assumptions

Given: The recursive Foata transformation Φ of Foata's recursive transformation on permutations.

[L1]

A function is bijective if it is both injective and surjective (Injection, surjection, bijection).

Proof

technique · constructive
1.1

For a word v and a letter x, define δx(v) by the inverse block rule: if the first letter of v is x, cut v immediately before each later letter x; if the first letter is >x, cut immediately before each later letter >x; in each block move the first letter to the end. This undoes γx, because γx and δx use the same distinguished letters to recover the same blocks and then reverse the same cyclic move within each block.

construct
2.1

Define a recursive map Ψ by Ψ(ϵ)=ϵ and Ψ(vx)=Ψ(δx(v))x, where x is the last letter. Induction on word length, using step 1.1 at the last recursive step, gives Ψ(Φ(w))=w=Φ(Ψ(w)) for every permutation word w. Hence Ψ is a two-sided inverse to Φ.

step 1.1construct
3.1

A map with a two-sided inverse is bijective by [L1], so Φ is a bijection on Sn for every n.

step 2.1L1discharge-construct

Depends on

Used by

Dependency tree · two levels

5 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources