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LemmaStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (deepseek-v4-pro + claude-opus-5[1m])audited 2026-08-24
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The Frattini subgroup of a finite group is characteristic

Statement

For every finite group G, the subgroup Φ(G) is characteristic in G and hence normal.

Facts & Assumptions

Given: A finite group G and an automorphism α of G.

[F1]

For a finite group G, the Frattini subgroup is Φ(G)={MG:M is maximal proper}; if G=1, the empty intersection inside G is G (The Frattini subgroup Φ(G) as the intersection of the maximal subgroups of a finite group).

[F2]

A subgroup HG is characteristic when α(H)=H for every automorphism α of G (Characteristic subgroups).

Proof

technique · direct
1.1

If M is maximal proper, then α(M) is proper and maximal: any subgroup strictly between α(M) and G pulls back under α1 to one strictly between M and G. Thus α permutes the family of maximal proper subgroups.

givenF1algebra
2.1

An automorphism carries an intersection to the intersection of the images, so step 1.1 and [F1] give α(Φ(G))=Φ(G). This is characteristicity by [F2]. Every inner automorphism is an automorphism, so Φ(G) is normal. The same argument covers G=1.

step 1.1F1F2algebra

Depends on

Used by

Dependency tree · two levels

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Sources