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The Frattini subgroup of a finite group is characteristic
Statement
For every finite group , the subgroup is characteristic in and hence normal.
Facts & Assumptions
Given: A finite group and an automorphism of .
For a finite group , the Frattini subgroup is ; if , the empty intersection inside is (The Frattini subgroup as the intersection of the maximal subgroups of a finite group).
A subgroup is characteristic when for every automorphism of (Characteristic subgroups).
Proof
If is maximal proper, then is proper and maximal: any subgroup strictly between and pulls back under to one strictly between and . Thus permutes the family of maximal proper subgroups.
An automorphism carries an intersection to the intersection of the images, so step 1.1 and [F1] give . This is characteristicity by [F2]. Every inner automorphism is an automorphism, so is normal. The same argument covers .
Depends on
Used by
- Generation of a finite group is detected modulo its Frattini subgroup Corollary
- A nonsurjective homomorphism need not carry the Frattini subgroup into the target Frattini subgroup Counterexample
- Automorphisms act linearly on the Frattini quotient Theorem
- The Frattini quotient is the largest elementary abelian quotient of a finite p-group Theorem
Dependency tree · two levels
5 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- D. A. Craven, The Theory of p-Groups, §2.2 (standard reference, not scraped)
- K. Conrad, Generating Sets, §6 (standard reference, not scraped)