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LemmaStatement: Literature-sourcedProof: AI-adaptedverified 2026-09-24 (gpt-6-sol)
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Countable proper local restrictions of a Fredholm map

Statement

Assume the Axiom of Choice. Let P:M→N be a Ch Fredholm map, h≥1, between Hausdorff second-countable real Banach manifolds. There is a countable family of subsets Cj⊂M whose interiors cover M. For each j there are a source open set Wj and a target chart Vj such that Cj is closed relative to Wj, P(Wj)⊂Vj, P∣Cj:Cj→Vj is proper, and in coordinates on Wj,Vj the map has Fredholm normal form (u,v)⟼(u,gj(u,v)), where v and the target obstruction coordinate are finite-dimensional. Proper means that the inverse image of each compact subset of Vj is compact. The conclusion includes M=∅, with an empty family.

Facts & Assumptions

Given: AC and the map in the statement.

[F1]

Every point has a normal-form neighbourhood with product source coordinates U×A, where U is open in a Banach range space and A is open in a finite-dimensional kernel space (Local finite-dimensional reduction for a Fredholm map).

[F2]

The source is second countable (Countable base Banach manifold and smooth map).

Proof

technique · direct
1.1

If M is empty, the empty family works. Otherwise fix x∈M and use [F1] to obtain W, a source coordinate diffeomorphism T:W→U×A, and a target chart in which P(T−1(u,v))=(u,g(u,v)). Write T(x)=(ux,vx). Choose radii a,b>0 small enough that the closed balls B‾a(ux)⊂U and B‾b(vx)⊂A. Set Cx:=T−1(B‾a(ux)×B‾b(vx)). Then Cx is closed relative to W, and its interior in M contains x.

F1givenchoose
2.1

The restriction P∣Cx:Cx→V is proper. To see this, let K⊂V be compact and take a sequence (zi) in Cx∩P−1(K). After a subsequence P(zi) converges in K; in target coordinates its first components ui therefore converge to some u∈B‾a(ux). The vi lie in the compact finite-dimensional ball B‾b(vx), so a further subsequence converges to v∈B‾b(vx). Continuity of T−1 and P gives zi→T−1(u,v)∈Cx∩P−1(K). This subset is metrizable through T, so sequential compactness implies compactness. The argument uses no compactness of a ball in the Banach range coordinate.

step 1.1algebra
3.1

The interiors of the Cx form an open cover of M. By [F2], under AC every open cover has a countable subcover: for each member of a countable base that is contained in some cover member, choose one such member. Keep the corresponding countably many Cx, and index them by a subset of N. Their interiors still cover M, and each retains the properties proved in steps 1.1–2.1.

F2step 1.1step 2.1choose∎

Depends on

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Sources