Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generated
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The projective group Γˉ(2) is torsion-free and acts freely

Statement

The only torsion elements of Γ(2) are ±I; equivalently Γˉ(2)=Γ(2)/{±I} is torsion-free and has no elliptic fixed points on H. In particular Γ(2) has no elliptic points and every point of H has trivial stabiliser in Γˉ(2).

Facts & Assumptions

Given: Γ(2)={γ∈SL2(Z):γ≡I(mod2)} with image Γˉ(2)≤PSL2(Z) (The principal congruence subgroup Gamma(2), Congruence modulo an integer: a≡b(modn) when n∣(a−b), including the moduli 0 and 1); the action of PSL2(Z) on H (The modular group and its action on the upper half-plane).

[F1]

A matrix γ=(abcd)∈Γ(2) satisfies a≡d≡1(mod2) and b≡c≡0(mod2), and ad−bc=1 (The principal congruence subgroup Gamma(2), Congruence modulo an integer: a≡b(modn) when n∣(a−b), including the moduli 0 and 1).

[F2]

A nonidentity element of PSL2(R) represented by A∈SL2(R) is either parabolic (conjugate to a nonzero translation) or, with two fixed points on C^, is conjugate to z↦λz, λ≠0,1, and tr⁡(A)2=λ+2+λ−1; it is elliptic exactly when ∣λ∣=1 (Nonidentity Möbius transformations are parabolic or conjugate to a dilation, with the projective trace invariant).

[F3]

Order and torsion in a group; a nonidentity element of PSL2(R) with a fixed point in H is conjugate to a rotation z↦eiθz, and every point of H with nontrivial stabiliser in PSL2(Z) is PSL2(Z)-equivalent to i, ω or ω+1 (The order ∣G∣ of a finite group and the order ord⁡(g) of an element, with ord⁡(g)=∞ when no positive power of g is the identity, The standard fundamental domain, boundary identifications and elliptic stabilisers, Nonidentity Möbius transformations are parabolic or conjugate to a dilation, with the projective trace invariant).

Proof

1.1F1F2givenalgebra

Suppose γ∈Γ(2) has a nontrivial finite-order class in PSL2(Z). By [F2] it cannot be parabolic, since a nonzero translation has infinite order. Thus it is conjugate to z↦λz with λ≠1 a root of unity, and (tr⁡γ)2=λ+2+λ−1=2+2cos⁡θ<4. The trace a+d is an even integer by [F1], so ∣a+d∣<2 forces a+d=0. Hence d=−a, where a is odd, and the determinant equation gives bc=−a2−1≡2(mod4). But b,c are even, so bc≡0(mod4), a contradiction. Therefore a finite-order projective class is trivial and its representative is ±I. In particular the only torsion matrices in Γ(2) are ±I.

2.1F3step 1.1givenalgebra∎

For any τ∈H, its PSL2(Z)-stabiliser is conjugate to a subgroup of the finite stabilisers in the standard domain [F3]. Thus every matrix in Γ(2) fixing τ has a finite-order projective class. By 1.1 it is ±I, so its class in Γˉ(2) is the identity. Hence Γˉ(2) is torsion-free and acts freely on H, and there are no elliptic points modulo scalars.

Depends on

Used by

Dependency tree · two levels

49 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources