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A Gaussian maximizes scalar differential entropy at fixed variance

Statement

Assume AC. Let V have a Lebesgue density p with ∫p(x)∣ln⁡p(x)∣ dx<∞, finite mean μ, and positive finite variance v=E[(V−μ)2]. Define h(V):=−∫p(x)ln⁡p(x) dx. Then h(V)≤12ln⁡(2πev), with equality exactly when V∼N(μ,v).

Facts & Assumptions

Given: AC and a real random variable with a density whose entropy integrand is absolutely integrable, finite mean, and positive finite variance.

[A1]

The Axiom of Choice: AC is required by the stated measure-theoretic KL convention and the Gaussian-law definitions.

[F1]

Kullback–Leibler divergence: for P≪Q, D(P∥Q)=∫ln⁡(dP/dQ) dP.

[F2]

Kullback–Leibler divergence is nonnegative: for probability measures, D(P∥Q)≥0, with equality exactly when P=Q.

[F3]

Standard normal and normal laws and A positive-definite multivariate normal law has its Gaussian density: for v>0, N(μ,v) has density (2πv)−1/2exp⁡(−(x−μ)2/(2v)).

[F5]

Proof

1.1A1F1F3F4F5given

Let q be the positive density in [F3]. Since q(x)>0 for every x, the law with density p is absolutely continuous with respect to the Gaussian law. Its KL divergence is well-defined by [F1]. The absolute entropy-integrability hypothesis and finite second moment make each term in the following expansion integrable.

2.1A1F1F2F3F4F5step 1.1algebra∎

Expanding ln⁡(p/q) and integrating gives D(PV∥N(μ,v))=−h(V)+12ln⁡(2πv)+E[(V−μ)2]2v=−h(V)+12ln⁡(2πev). By [F2] this is nonnegative, proving the bound; equality holds exactly when the two laws coincide, again by [F2].

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