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LemmaStatement: Literature-sourcedProof: AI-generatedprecheck passaudited 2026-09-12
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A Chomsky-normal-form parse tree of height h has yield length at most 2h1

Statement

Let G be a context-free grammar in Chomsky normal form, and let T be a parse tree for G of height h1. If y(T) is the yield of T, then y(T)2h1.

Facts & Assumptions

Given: A Chomsky-normal-form grammar G and a parse tree T of height h1.

[L1]

By Parse trees and their yields, the yield of a parse tree is the left-to-right list of its terminal leaves, and every internal node is labeled by a variable together with one production used at that node.

[L2]

By Chomsky normal form, every production in a CNF grammar is either ABC, Aa, or the exceptional start rule Sε.

Proof

technique · direct
1.1

We induct on the height h. If h=1, then the root is already a leaf. By [L1], a leaf at the root can only be the variable leaf corresponding to the exceptional CNF rule Sε from [L2]. Thus y(T)=ε, so y(T)=01=20.

L1L2given
2.1

Suppose h>1. If the root uses a terminal production Aa, then the yield has length 1, so the bound is immediate. Otherwise the root uses a binary production ABC by [L2]. The two child subtrees have heights at most h1, so by the induction hypothesis each contributes at most 2h2 terminal leaves. Therefore y(T)2h2+2h2=2h1.

L1L2step 1.1induction
3.1

The bound holds for height 1 and is preserved when the height increases, so every CNF parse tree of height h has yield length at most 2h1.

step 1.1step 2.1

Depends on

Used by

Dependency tree · two levels

17 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources