Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-04
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

The coefficientwise limits multiply back to the original polynomial

Statement

Let A be I-adically complete and separated, and let (gr,hr)r≥1 be monic polynomial lifts of fixed degrees such that:

  1. f−grhr∈Ir[T] for every r≥1, and
  2. the coefficient sequences of gr and hr are I-adically Cauchy.

Then the coefficientwise limits g,h∈A[T] exist and satisfy f=gh.

Facts & Assumptions

Given: An I-adically complete and separated ring A, a polynomial f∈A[T], and stagewise lifts (gr,hr) as above.

[L1]

The Hensel correction sequences are coefficientwise I-adically Cauchy (Successive Hensel corrections are Cauchy).

[L2]

Completeness gives limits of I-adic Cauchy sequences, and separatedness means that an element lying in every Ir is zero (Separated and complete filtered modules).

Proof

technique · take coefficientwise limits and use separatedness on each coefficient
1.1L1L2given

By completeness and [L2], each coefficient sequence of gr and of hr has a limit in A. Since the degrees are fixed and the leading coefficients are always 1, these limits assemble into monic polynomials g,h∈A[T] of the same degrees.

2.1step 1.1givenalgebra

Fix a coefficient index j of the product. Only finitely many coefficient pairs contribute to the Tj-coefficient of grhr, so ordinary continuity of finite sums and products shows that the Tj-coefficient of grhr converges to the Tj-coefficient of gh.

3.1L2step 2.1givenalgebra

For every r, the coefficient of Tj in f−grhr lies in Ir by hypothesis. Passing to the limit in step 2.1 shows that the coefficient of Tj in f−gh lies in every Ir. By separatedness and [L2], that coefficient is 0. Since this holds for every j, one has f=gh.

4.1step 1.1step 3.1∎

Therefore the coefficientwise limits of the iterative factors multiply back to the original polynomial.

Depends on

Used by

Dependency tree · two levels

5 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources