Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-6-luna)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Finite comatrix coalgebras exist

Statement

For a field k and an integer n≥1, let En be the vector space with basis cij for 1≤i,j≤n. The linear maps defined on this basis by Δ(cij)=∑ℓ=1nciℓ⊗cℓj,ε(cij)=δij make En a coalgebra. In particular, the one-dimensional space with basis c and maps Δ(c)=c⊗c, ε(c)=1 is a nonzero coalgebra.

Facts & Assumptions

Given: A field k, an integer n≥1, and the vector space En with the stated basis.

[F1]

The coalgebra axioms are coassociativity and the two counit identities, with the associator and unit maps specified in the definition (Coalgebra and coalgebra map over a field).

[F3]

The tensor associator identifies (En⊗En)⊗En with En⊗(En⊗En) (Associator naturality, pentagon, unit triangle and symmetry hexagons on elementary tensors).

[F4]

A set map from a free basis extends uniquely to a linear map (Universal property of the free module on a set).

[F5]

Tensoring linear maps gives well-defined linear maps, with (f⊗g)(x⊗y)=f(x)⊗g(y) (Module homomorphisms induce tensor-product homomorphisms functorially).

Proof

1.1givenF4construct

The displayed assignments on the basis extend uniquely to linear maps Δ:En→En⊗En and ε:En→k by [F4].

2.1givenstep 1.1F1F2F3F5algebra

On a basis vector, the left side of coassociativity in En⊗(En⊗En) is α((Δ⊗id)Δ(cij))=∑m,ℓcim⊗(cmℓ⊗cℓj), while the right side is (id⊗Δ)Δ(cij)=∑ℓ,mciℓ⊗(cℓm⊗cmj). Interchanging the dummy indices m and ℓ in the finite right-hand sum makes the sums identical. Since both sides are linear and the cij form a basis, coassociativity holds on En.

2.2givenstep 1.1F1F5algebra

For every i,j, λ(ε⊗id)Δ(cij)=∑ℓδiℓcℓj=cij and ρ(id⊗ε)Δ(cij)=∑ℓciℓδℓj=cij. Linearity extends both identities from the basis to En.

3.1step 2.1step 2.2F1given∎

Steps 2.1 and 2.2 verify the coalgebra axioms of [F1]. At n=1 the displayed formulas give Δ(c)=c⊗c and ε(c)=1; because c is a basis vector it is nonzero.

Depends on

Used by

Dependency tree · two levels

18 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources