Alphabeta Math
ExampleConstruction: AI-generatedVerification: AI-generatedPipeline-generated
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A two-dimensional comodule and its coefficient matrix

Example

Let C=E2 be the 2×2 (four-dimensional) comatrix coalgebra from Finite comatrix coalgebras exist, with basis c11,c12,c21,c22 and structure Δ(cij)=∑ℓ=12ciℓ⊗cℓj,ε(cij)=δij. Let M have basis v1,v2 and set ρ(vj)=∑i=12vi⊗cij. Then M is a right C-comodule and its coefficient matrix is (cij).

Facts & Assumptions

Given: A field k, the 2×2 (four-dimensional) comatrix coalgebra structure above, and the two-dimensional vector space M with basis v1,v2.

[F1]

A right coaction must satisfy (ρ⊗id⁡)ρ=(id⁡⊗Δ)ρ and (id⁡⊗ε)ρ=id⁡. (Right comodules, comodule maps, and subcomodules)

[F2]

For a finite basis, coefficient identities Δ(cij)=∑ℓciℓ⊗cℓj and ε(cij)=δij define a right-comodule structure by the displayed basis formula. (Kernels, images, quotients, and matrix coefficients of comodules)

[F3]

For n=2, Finite comatrix coalgebras exist supplies four basis vectors cij and the displayed coproduct and counit, with a proof that the assignments extend linearly and satisfy coassociativity and both counit identities.

[F4]

A vector space with a finite basis of n elements has dimension n. Thus M has dimension 2 and E2 has dimension 4. (Finite-dimensional vector space, and its dimension dim⁡FV; infinite-dimensional means having no finite basis)

Verification

Given: The basis and coefficient maps of E2 and the two-dimensional vector space M.

1.1givenF1construct

Define ρ on v1,v2 by the two displayed finite sums and extend linearly. Since v1,v2 is a basis, this determines a unique linear map M→M⊗C.

2.1F1F3step 1.1algebra

For j=1,2, expand the left coaction composite as (ρ⊗id⁡)ρ(vj)=∑i,ℓ=12vi⊗ciℓ⊗cℓj. The right composite is (id⁡⊗Δ)ρ(vj)=∑i,ℓ=12vi⊗ciℓ⊗cℓj using the coproduct formula in [F3]. Thus the composites agree on the basis and hence on every vector.

2.2F1F3step 1.1algebra

For j=1,2, (id⁡⊗ε)ρ(vj)=∑i=12viδij=vj. Linearity extends the counit identity to all of M. Together with the coalgebra structure on C from [F3], this makes the displayed map a right coaction.

3.1F2step 1.1step 2.1step 2.2

By the ordered basis formula for a right coaction, the coefficient in row i, column j is exactly cij; the identities in [F2] are the corresponding comatrix identities.

4.1F3F4step 1.1step 2.1step 2.2step 3.1∎

Steps 1.1, 2.1, and 2.2 verify the right coaction equations using the finite comatrix coalgebra of [F3], and step 3.1 identifies its coefficient matrix; [F4] gives the stated dimensions of the two objects.

Depends on

Used by

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Dependency tree · two levels

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Sources