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Every holomorphic line bundle on a compact Riemann surface has a meromorphic section

Statement

Assume the full Axiom of Choice (The Axiom of Choice). Let X be a compact connected Riemann surface, let E→X be a holomorphic line bundle, and let p∈X. Then there is a global meromorphic section s of E that is holomorphic on X∖{p} and has a pole at p.

Facts & Assumptions

Given: Full AC, the compact connected Riemann surface X, a holomorphic line bundle E→X, and a point p∈X.

[F1]

Full AC implies ACω; compatible Riemannian and Hermitian metrics on X and E therefore exist (The Axiom of Choice, AC implies DC implies countable choice, Hermitian metric and L2 pairing on a compact Riemann surface).

[F2]

The global degree-one Dolbeault group is H0,1(X,E):=Ω0,1(X,E)/∂ˉEΩ0,0(X,E); its zero class consists exactly of forms ∂ˉEu for global smooth sections u (Holomorphic line bundles and meromorphic sections on a Riemann surface, Dolbeault cohomology of a compact riemann surface is finite dimensional).

[F3]

The global degree-one Dolbeault group H0,1(X,E) is finite-dimensional for a compact Riemann surface and holomorphic line bundle (Dolbeault cohomology of a compact riemann surface is finite dimensional).

[F4]

In a holomorphic frame e, ∂ˉE(fe)=(∂ˉf)e, and ∂ˉEu=0 exactly when u is holomorphic (Holomorphic line bundles and meromorphic sections on a Riemann surface).

[F5]

A meromorphic section is given by meromorphic local coefficients satisfying the frame transition law (Holomorphic line bundles and meromorphic sections on a Riemann surface).

[F6]

A Riemann surface is nonempty and connected and is covered by holomorphic coordinate charts (Riemann surfaces and holomorphic atlases).

[F7]

If K0 is compact and contained in an open set U of a smooth manifold, there is a smooth cutoff supported in U and equal to 1 near K0 (A manifold bump for a compact set inside an open set).

[F8]

On a one-dimensional complex manifold, (0,2)-forms vanish (Bigraded complex forms and the Dolbeault operators).

Proof

technique · local principal parts and finite-dimensional Dolbeault cohomology
1.1F1F3F4F6F7given

By [F1], choose compatible metrics on X and E to apply [F3], and set m=dim⁡CH0,1(X,E)<∞. Choose a holomorphic coordinate disk U about p with z(p)=0 and a holomorphic frame e for E on U. Choose a smaller closed coordinate disk K0⊂U whose interior contains p, and by [F7] choose χ∈Cc∞(U) equal to 1 near K0; its support is compact because X is compact.

2.1F4F6F7F8step 1.1given

For each j=1,…,m+1, define σj=χz−je on U∖{p} and extend it by zero to X∖{p}. This is smooth away from p because χ is supported inside U. Define θj=∂ˉEσj on X∖{p}. On a neighborhood of p one has χ=1, so σj=z−je there and θj=0; thus θj extends by zero to a global smooth E-valued (0,1)-form. Every such form is ∂ˉE-closed because (0,2)=0 by [F8].

3.1F2F3step 1.1step 2.1algebra

Define T:Cm+1→H0,1(X,E) by T(c)=[∑j=1m+1cjθj]. This is complex-linear by [F2]. Choose a basis of its m-dimensional target; the equation T(c)=0 then has m homogeneous linear equations in m+1 unknowns. Row reduction has at most m pivots and leaves a free variable, so choose c≠0 in the kernel, including when m=0. Put θ=∑jcjθj; its Dolbeault class is zero.

4.1F1F2F3step 3.1

Since [θ]=0, the quotient definition [F2] supplies a global smooth section u of E with ∂ˉEu=θ. The only choice hypothesis is inherited through metric existence and finite-dimensional cohomology; the kernel calculation is finite.

5.1F4F5step 2.1step 4.1construct∎

On X∖{p} set s=∑jcjσj−u. Then ∂ˉEs=0, so s is holomorphic there by [F4]. Near p, where χ=1, its coefficient in the frame e is ∑jcjz−j−ue(z). Since θ=0 near p, [F4] makes ue holomorphic there; the nonzero Laurent polynomial ∑jcjz−j has a pole, so this coefficient has the same nonzero principal part. Thus s extends meromorphically across p, has a pole there, is holomorphic elsewhere, and is not identically zero.

Depends on

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