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Homogeneous margin constraints satisfy MFCQ

Statement

For homogeneous sample margins qi of degree L>0, every feasible point of the problem min⁡θ12∥θ∥22 subject to qi(θ)≥1 satisfies MFCQ in the margin convention.

Facts & Assumptions

Given: The degree-L homogeneous classifier margins and a feasible point θ.

[F1]

Homogeneous classifier margins and exponential training risk: each sample margin satisfies qi(cθ)=cLqi(θ) for every c>0, with L>0.

[F2]

Euler identity for Clarke subgradients of homogeneous margins: for hi∈∂∘qi(θ), ⟨θ,hi⟩=Lqi(θ) when θ≠0.

[F3]

KKT conditions and MFCQ for margin constraints: at a feasible point, MFCQ in margin form asks for one direction whose pairing with every Clarke subgradient of every active margin is strictly positive.

Proof

technique · use the parameter vector itself as the strict feasible direction
1.1F1givenalgebra

By [F1], qi(0)=qi(2⋅0)=2Lqi(0). Since 2L>1, this forces qi(0)=0 for every i. Thus a feasible point cannot be θ=0, because feasibility requires every margin to be at least one.

2.1F2F3step 1.1givenchoosealgebra∎

Choose v=θ. If no constraint is active, the universal condition in [F3] is vacuous. Otherwise, for each active index i, qi(θ)=1 and every hi∈∂∘qi(θ) satisfies ⟨hi,v⟩=⟨θ,hi⟩=Lqi(θ)=L>0 by [F2]. Hence the same direction v satisfies MFCQ for all active margins.

Depends on

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