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The stated incoherence bound implies the Lasso restricted eigenvalue condition

Statement

Let n≥1, 1≤s≤d, and let X∈Rn×d satisfy the incoherence condition of Fixed-design incoherence condition. For every S⊆{1,…,d} with ∣S∣≤s and every v∈C(S), ∥Xv∥22n≥12∥vS∥22. Consequently the restricted eigenvalue condition of Restricted eigenvalue condition on the Lasso cone holds with κ2=1/2.

Facts & Assumptions

Given: X∈Rn×d, n≥1, 1≤s≤d, and the incoherence bound max⁡j,k∣(XTX/n−I)jk∣≤1/(14s).

[F1]

Put G=XTX/n. The incoherence bound is entrywise and equals 1/(14s) (Fixed-design incoherence condition).

[F2]

C(S) means ∥vSc∥1≤3∥vS∥1 (Restricted eigenvalue condition on the Lasso cone).

[F3]

For a set S of at most s coordinates, ∥vS∥12≤∣S∣∥vS∥22≤s∥vS∥22 (The Cauchy-Schwarz inequality for finite sums).

[F4]

vTGv=∥Xv∥22/n≥0 for every v, by the definition of G.

Proof

1.1F1F3algebra

Write v=vS+vSc. Since vS and vSc have disjoint supports, [F1] gives vSTGvS≥∥vS∥22−114s∥vS∥12≥1314∥vS∥22, where the second inequality uses [F3].

1.2F1F2F3F4algebra

The same disjoint-support fact makes vSTIvSc=0. Thus ∣vSTGvSc∣≤114s∥vS∥1∥vSc∥1≤314s∥vS∥12≤314∥vS∥22, using [F1], [F2] and [F3]. Also vScTGvSc≥0 by [F4].

2.1step 1.1step 1.2algebra∎

Expanding vTGv and using steps 1.1–1.2 gives vTGv≥(1314−2314)∥vS∥22=12∥vS∥22. This is the stated restricted eigenvalue inequality, including vS=0 (then the cone condition forces v=0, for which both sides are zero).

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