Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-generatedprecheck passaudited 2026-08-01
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  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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An injective Darboux function on an interval is strictly monotone

Statement

An injective function f:I→R on an interval I with the intermediate value property is strictly monotone.

Facts & Assumptions

Given: An injective Darboux function f on an interval I.

[L1]

The pointwise Darboux property in The intermediate value property (Darboux property) of a function on an interval: the image of every subinterval is order-convex attains every value between f(a) and f(b) on [a,b].

Proof

technique · contradiction
1.1

For any a<b<c in I, f(b) must lie strictly between f(a) and f(c). Indeed, if it lies above both, a value strictly between max⁡{f(a),f(c)} and f(b) is attained once in (a,b) and once in (b,c), contradicting injectivity; the case below both is analogous.

assume-contraL1given
2.1

Fix a<b. If f(a)<f(b), step 1.1 forces f(x)<f(y) for every x<y in I; inserting points between or beyond a,b proves all possible placements. If f(b)<f(a), the symmetric argument gives strict decrease.

step 1.1L2cases
3.1

Injectivity excludes equality, so one of the two alternatives holds and f is strictly monotone.

step 2.1discharge-contradiction∎

Depends on

Used by

Dependency tree · two levels

14 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources