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LemmaStatement: Literature-sourcedProof: AI-generatedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-01
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An injective Darboux function on an interval is strictly monotone

Statement

An injective function f:IRf:I\to\mathbb R on an interval II with the intermediate value property is strictly monotone.

Facts & Assumptions

Given: An injective Darboux function ff on an interval II.

[L1]

The pointwise Darboux property in The intermediate value property (Darboux property) of a function on an interval: the image of every subinterval is order-convex attains every value between f(a)f(a) and f(b)f(b) on [a,b][a,b].

Proof

technique · contradiction
1.1

For any a<b<ca<b<c in II, f(b)f(b) must lie strictly between f(a)f(a) and f(c)f(c). Indeed, if it lies above both, a value strictly between max{f(a),f(c)}\max\{f(a),f(c)\} and f(b)f(b) is attained once in (a,b)(a,b) and once in (b,c)(b,c), contradicting injectivity; the case below both is analogous.

assume-contraL1given
2.1

Fix a<ba<b. If f(a)<f(b)f(a)<f(b), step 1.1 forces f(x)<f(y)f(x)<f(y) for every x<yx<y in II; inserting points between or beyond a,ba,b proves all possible placements. If f(b)<f(a)f(b)<f(a), the symmetric argument gives strict decrease.

step 1.1L2cases
3.1

Injectivity excludes equality, so one of the two alternatives holds and ff is strictly monotone.

step 2.1discharge-contradiction

Depends on

Used by

Dependency tree · next 3 levels

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