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CorollaryStatement: AI-adaptedProof: AI-generatedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-01
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A derivative has neither a removable discontinuity nor a jump discontinuity

Statement

A derivative has neither a removable discontinuity nor a jump discontinuity. Any discontinuity of a derivative is therefore essential in the classification of Discontinuity of ff at a point of its domain, and its classification: removable discontinuity, jump discontinuity and essential discontinuity, equivalently Rudin's discontinuities of the first and of the second kind.

Proof

technique · contradiction
1.1

Assume cc is removable. Choose a value strictly between the common punctured limit and g(c)g(c). On a sufficiently small punctured neighbourhood all values of gg lie on the limit side of that value, while the endpoint value lies on the other side, contradicting the intermediate value property on a segment ending at cc.

assume-contraL1L2choose
1.2

Assume cc is a jump. The open interval between the unequal one-sided limits contains a value different from g(c)g(c); choose such a value. Sufficiently close points on the two sides have values on opposite sides of the chosen value, while neither punctured side nor the point cc takes it, again contradicting the intermediate value property.

assume-contraL1L2choose
2.1

Thus neither kind of discontinuity can occur.

step 1.1step 1.2discharge-contradiction

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