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Integrability can be checked on simple root sl2 subalgebras
Statement
For a weight -module , integrability is equivalent to local finiteness for each simple-root subalgebra : every vector lies in a finite-dimensional -invariant subspace. This does not require finite-dimensional weight spaces or category- support.
Facts & Assumptions
Given: A weight module and a fixed simple index .
Integrability means local nilpotence of both and (Integrable kac moody module).
The simple generators satisfy , , (Contragredient lie algebra before the maximal ideal quotient).
Their nonzero opposite root spaces and the embedded Cartan make the three generators linearly independent (Kac moody root spaces are finite dimensional).
Proof
By F2 and F3 their span has exactly the three independent standard generators and brackets. Repeatedly using the three commutation relations puts every enveloping word into a linear combination of : an adjacent swap decreases the number of out-of-order pairs, and its commutator term has shorter word length. Induction on length and inversions terminates. On a weight vector , the last factor acts by the scalar , so the cyclic span is spanned by . Only spanning is needed, not PBW independence or semisimplicity.
For the reverse implication, let a vector lie in a finite-dimensional -invariant subspace . The operator is diagonalizable on : on each vector it has a finite eigen-expansion inherited from the ambient weight module, and polynomial interpolation in keeps its components in . Since is finite dimensional, only finitely many eigenvalues occur. By F2, and shift these eigenvalues by and . On an -eigenvector, a nonzero string of length greater than the number of eigenvalues would require more distinct eigenvalues than has. Thus both operators are nilpotent on , and locally nilpotent on . F1 gives integrability.
Assume integrability. For a weight vector , local nilpotence of permits only finitely many nonzero . For each of these finitely many vectors, local nilpotence of permits only finitely many nonzero . Their span in 1.1 is therefore finite dimensional and is the cyclic -submodule. Every vector of a weight module is a finite sum of weight vectors. The sum of their finite-dimensional cyclic submodules is again finite dimensional and invariant, proving local finiteness.
This works for every simple index. Zero vectors and the zero module have zero cyclic spans, while a one-dimensional cyclic submodule satisfies the same spectral argument. Each spanning calculation and each choice of a bound concerns only finitely many vectors; no choice principle or complete-reducibility theorem was used. Both implications are proved.
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Used by
Dependency tree · two levels
9 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Kleshchev, Lectures on Infinite Dimensional Lie Algebras (standard reference, not scraped)
- Perrin, Introduction to Kac-Moody Groups and Lie Algebras (standard reference, not scraped)