Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-generatedPipeline-generatedjudge pass (gpt-6-luna)verified 2026-10-22 (gpt-6.1-sol)
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

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A block-tail estimate for the largest coordinates

Statement

Let n,s∈N with n≥1 and 1≤s≤n, and let h∈Rn use one-based coordinate labels [n]={1,…,n}, with label j corresponding to library coordinate j−1. In real scalar expressions, a natural number denotes its canonical real image. Order the coordinates by decreasing ∣hj∣, breaking ties by increasing j. Let S consist of the first s indices, and partition Sc in this same order into consecutive nonempty blocks T1,…,Tq of size s, with only the last block possibly smaller; if Sc=∅, take q=0. Then ∥hSc∥2≤∥hS∥2+∥hSc∥1s.

Facts & Assumptions

Given: Integers n≥1, 1≤s≤n, a vector h∈Rn, the deterministic ordered coordinate list j1,…,jn, its first-s set S={j1,…,js}, and the finite successive tail blocks T1,…,Tq.

[F1]

The strict nullspace property: hS agrees with h on S and is zero on Sc; the coordinate labels are one-based with label j identified with library coordinate j−1.

[F2]

The p-norms ∥x∥p for rational p≥1, and ∥x∥∞: ∥v∥1=∑j∣vj∣ and ∥v∥2=(∑j∣vj∣2)1/2 on finite-dimensional real coordinate spaces.

[F4]

Laws of finite sums and finite products: finite sums preserve termwise inequalities and a sum of nonnegative terms is nonnegative.

[F5]

Squaring is monotone on the nonnegatives: for nonnegative a,b, a2≤b2 implies a≤b.

[F6]

The canonical natural ι(n)=n⋅1F of a field: a natural number used as a real scalar denotes its canonical real image.

[F7]

Canonical naturals are positive and strictly increasing: the canonical real image of s is positive for s≥1; if kr≤s as natural numbers, then their canonical real images satisfy kr≤s.

Proof

1.1givenF1F2F4F5algebra

If q=0, then Sc=∅ and the conclusion is 0≤∥hS∥2. If q≥1, write r=∣T1∣≤s. The order gives T1={js+1,…,js+r} and S={j1,…,js}, with ∣hjs+k∣≤∣hjk∣ for every 1≤k≤r. Termwise squaring and finite-sum monotonicity therefore give ∥hT1∥22=∑k=1r∣hjs+k∣2≤∑k=1r∣hjk∣2≤∑k=1s∣hjk∣2=∥hS∥22. Both norms are nonnegative, so [F5] gives ∥hT1∥2≤∥hS∥2.

2.1givenF2F3F4F5F6F7step 1.1algebra∎

For each 2≤r≤q, the preceding block Tr−1 has size s. Its last ordered coordinate has magnitude no greater than any earlier entry, hence no greater than the average magnitude on Tr−1. Every entry of Tr is no greater than that last entry. Put c=∥hTr−1∥1/s. Then each entry of Tr has magnitude at most c. If kr=∣Tr∣, termwise comparison gives ∥hTr∥22=∑j∈Tr∣hj∣2≤krc2≤sc2=∥hTr−1∥12s, using kr≤s as natural numbers: padding the sum of kr copies of the nonnegative number c2 by the remaining nonnegative copies gives the sum of s copies, by [F4]; [F6,F7] interpret these counts as real scalars. Since both sides are nonnegative, [F5] gives ∥hTr∥2≤∥hTr−1∥1s. The blocks are disjoint and finite. By [F6], [F7], the triangle inequality, step 1.1, and this block bound, ∥hSc∥2=∥∑r=1qhTr∥2≤∑r=1q∥hTr∥2≤∥hS∥2+1s∑r=1q−1∥hTr∥1≤∥hS∥2+∥hSc∥1s. This proves the claimed estimate, including a final block smaller than s.

Remarks

The tie-breaking rule makes the block partition deterministic. The proof uses only finite coordinate comparisons and the Euclidean triangle inequality; no choice axiom is used.

Depends on

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Sources