How statement and proof provenance work
The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.
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The opposite simple centralizer in a Kac Moody half vanishes
Statement
If satisfies for every , then . Likewise with for every is zero.
Facts & Assumptions
Given: A finite GCM and its maximal Cartan-disjoint quotient.
Every nonzero ideal meets the Cartan. (Kac moody algebra associated to a gcm).
Weights have one sign and distinct root coordinates. (Kac moody root spaces are finite dimensional).
Proof
Decompose into finitely many weights. For fixed , the brackets of its distinct components with have distinct weights, so each bracket is zero. It suffices to treat a homogeneous of positive degree . Let be the span of and all iterated applied to . Every such vector has degree with , so .
The space is stable under all by construction and under by its homogeneous spanning vectors. Induct on the number of positive adjoints to prove stability under . The base is . For already treated, lies in . Thus is an ideal, and by its positive degrees. F1 forces , hence . The sign-changing involution interchanges the two conclusions.
Sources
Source comparison: Kleshchev, Perrin Lemma 4.2.8, p.36; maximal-ideal argument as in Kleshchev §1.4.
Additional source: Perrin, section 4.2, at the numbered locators above.
Depends on
Used by
Dependency tree · two levels
4 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- Kleshchev, Lectures on Infinite Dimensional Lie Algebras — Perrin Lemma 4.2.8, p.36; maximal-ideal argument as in Kleshchev §1.4 (standard reference, not scraped)
- Nicolas Perrin, Introduction to Kac-Moody groups and Lie algebras, section 4.2 (standard reference, not scraped)