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LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-10
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Serre elements vanish before Serre generation

Statement

For every finite GCM and ij, the maximal-ideal quotient satisfies (adei)1aijej=0 and (adfi)1aijfj=0. This asserts vanishing, without yet asserting generation of the defining ideal.

Facts & Assumptions

Given: The standard simple generators in g(A), and i≠j.

[F1]

A negative vector killed by all opposite simple generators is zero. (The opposite simple centralizer in a Kac Moody half vanishes).

[F2]

The algebra g(A) is the quotient of g~(A) by the largest Cartan-disjoint ideal and retains the generator names h,ei,fi. (Kac moody algebra associated to a gcm).

[F3]

Before the quotient, the generators satisfy [h,h]=0, [h,ei]=αi(h)ei, [h,fi]=αi(h)fi, and [ei,fj]=δijhi. (Contragredient lie algebra before the maximal ideal quotient).

Proof

1.1

The relations of F3 descend through the quotient of F2. For operators E,F,H with [E,F]=H and [H,F]=2F, the identity [E,Fm]=mFm1(Hm+1) follows from [E,Fm+1]=[E,Fm]F+FmH and HF=F(H2), starting at m=1. Take the adjoint operators of ei,fi,hi. On v=fj, Ev=0 and Hv=aijv. For m=1aij, the identity gives EFmv=m(aijm+1)Fm1v=0.

F2F3given
2.1

For k{i,j}, adek commutes with adfi and kills fj, so kills Fmv. For k=j, it commutes with F and sends fj to hj, so sends Fmv to Fmhj. Now Fhj=ajifi and F2hj=0. If m2 this vanishes; if m=1, aij=0 and the symmetric-zero axiom gives aji=0. Thus all ek kill the negative Serre vector.

F2F3givenstep 1.1
3.1

F1 kills this vector in n. The sign-changing involution descending in F2 proves the positive relation with the same exponent. At no point has an ideal been asserted to be generated by these vectors.

F1F2step 1.1step 2.1

Sources

Source comparison: Kleshchev, §1.4 Serre vanishing and Lemma 3.1.1; Perrin Propositions 4.2.6–4.2.7, pp.35–37.

Additional source: Perrin, section 4.2, at the numbered locators above.

Depends on

Used by

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Sources