LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-06

How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Koszul Resolution Minimality Maximal Ideal Sequence

Statement

Let $(R, m)$ be a local ring and let $M$ be a finite free $R$ -module. If $x \subseteq m$ and $K (x; M)$ resolves $M / (x) M$ , then it is a minimal free resolution because every differential matrix has entries among the $x_{i}$ .

Facts & Assumptions

Given: The rings, finite sequences, modules, and local hypotheses stated in the claim. The declared prerequisites used here are Koszul Complex Resolves A Regular Quotient, Minimal Free Resolution Over A Local Ring, Koszul Differential Coordinate Formula.

Proof

technique · direct

1.1givenalgebra

In the exterior bases, every matrix coefficient of $d$ is $0$ or $\pm x_{i}$ , hence belongs to $m$ .

2.1step 1.1algebra∎

Since $M$ is finite free, every term $M \otimes_{R} ⋀^{p} R^{n}$ is finite free. The assumed acyclicity and degree-zero quotient therefore make the Koszul complex a finite free resolution, and the containment from step 1.1 is precisely the local minimality criterion.

Depends on

Used by

Complete Intersection Betti Numbers Binomial Corollary
Koszul Resolution Betti Table Complete Intersection Example

Dependency tree · two levels

12 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources

The Stacks Project, Koszul complexes and regular sequences (standard reference, not scraped)