Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-07
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

LCH Urysohn cutoff

Statement

Assuming Dependent Choice as in Urysohn's lemma, under the axiom of dependent choice: in a normal space two disjoint closed sets are separated by a continuous function into [0,1], and conversely such a space is normal, if K⊆U with K compact and U open in an LCH space X, then some f∈Cc(X) satisfies 1K≤f≤1U.

Facts & Assumptions

Given: K⊆U, with K compact and U open.

[L1]

Every compact set in an LCH space has an open neighbourhood V with K⊆V⊆V‾⊆U and compact V‾. (In a locally compact Hausdorff space every open set containing a point contains an open set containing it whose closure is compact and still inside; such a space is regular)

[L2]

Proof

technique · direct
1.1L1L2choose

Choose V as in [L1]. The compact Hausdorff space V‾ is normal; apply [L2] there to K and V‾∖V, obtaining h=1 on K and h=0 on V‾∖V.

2.1step 1.1construct∎

Extend h by 0 off V‾. Continuity of h on V‾ and its vanishing on the boundary V‾∖V make the extension continuous; it is supported in V‾⊆U, is 1 on K, and belongs to Cc(X).

Depends on

Used by

Dependency tree · two levels

28 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources