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LemmaStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (gpt-5.6-terra)audited 2026-08-28
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Levi pseudoconvexity does not depend on the defining function

Statement

Let ΩCm have C2 boundary, let pΩ, and let ρ and ρ~ be two C2 defining functions near p. Then on complex tangent vectors at p, the Levi forms differ by a positive scalar factor. In particular, the sign condition in the definition of Levi pseudoconvexity is independent of the defining function.

Facts & Assumptions

Given: A boundary point pΩ and two C2 defining functions ρ and ρ~ near p.

[L1]

Levi pseudoconvexity is stated in terms of the Levi form on complex tangent vectors of a defining function (Levi pseudoconvex domains).

Proof

technique · direct
1.1

Because ρ and ρ~ vanish on the same C2 hypersurface, have nonzero differentials there, and define the same negative side, one has ρ~=hρ near p for a positive C1 function h.

L1given
2.1

Let v be a complex tangent vector at p, so ρ(p)v=0. The second-order expansion of hρ at p uses only first derivatives of h because ρ(p)=0; every mixed product term contains ρ(p)v or its conjugate and therefore vanishes on v. Consequently Lρ~(p;v)=h(p)Lρ(p;v). Since h(p)>0, the two Levi forms have the same sign on complex tangent vectors.

step 1.1algebra

Depends on

Used by

Dependency tree · two levels

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Sources