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Levi pseudoconvexity does not depend on the defining function
Statement
Let have boundary, let , and let and be two defining functions near . Then on complex tangent vectors at , the Levi forms differ by a positive scalar factor. In particular, the sign condition in the definition of Levi pseudoconvexity is independent of the defining function.
Facts & Assumptions
Given: A boundary point and two defining functions and near .
Levi pseudoconvexity is stated in terms of the Levi form on complex tangent vectors of a defining function (Levi pseudoconvex domains).
Proof
Because and vanish on the same hypersurface, have nonzero differentials there, and define the same negative side, one has near for a positive function .
Let be a complex tangent vector at , so . The second-order expansion of at uses only first derivatives of because ; every mixed product term contains or its conjugate and therefore vanishes on . Consequently Since , the two Levi forms have the same sign on complex tangent vectors.
Depends on
Used by
Dependency tree · two levels
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Sources
- Jiří Lebl, Tasty Bits of Several Complex Variables, §2.3 (standard reference, not scraped)
- Harold P. Boas, Lecture Notes on Several Complex Variables, §3.3.1 (standard reference, not scraped)