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LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck passaudited 2026-10-02
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The logarithmic unit image is discrete

Statement

Assume the Axiom of Choice. The subgroup λ(OK×)⊂H is discrete; equivalently, every bounded subset of H meets λ(OK×) in finitely many points.

Facts & Assumptions

Given: The Axiom of Choice, a number field K of degree n=[K:Q] with logarithmic embedding λ and hyperplane H (Logarithmic embedding of a number field), and a bounded subset C⊆H.

[F1]

The map λ is given by λ(x)=(log⁡∣σ1x∣,…,log⁡∣σr1x∣,2log⁡∣τ1x∣,…,2log⁡∣τr2x∣), with σ1,…,σr1 the real embeddings and τ1,…,τr2 one embedding from each complex conjugate pair (Logarithmic embedding of a number field, Archimedean embeddings and signature).

[F2]

For every unit u∈OK× one has λ(u)∈H, so λ(OK×) is a subgroup of the finite-dimensional real vector space H (Unit logarithms lie in the trace-zero hyperplane).

[F3]

For a subgroup Γ of a finite-dimensional real vector space with the topology induced by a norm, Γ is discrete if and only if every bounded subset of the space meets Γ in a finite set (Discrete subgroups of a real vector space are lattices).

[F4]

The natural logarithm is strictly increasing with inverse the exponential function on (0,∞) (Order, continuity, range, and the product, quotient, and reciprocal laws for the natural logarithm, The exponential function is strictly increasing, The natural logarithm as the inverse of the exponential function); hence for real a>0 and real t, a≤et if and only if log⁡a≤t, and similarly log⁡a≥−t if and only if a≥e−t.

[F5]

For fixed n≥1 and R≥1, only finitely many monic integer polynomials of degree at most n have all their complex roots of modulus at most R (Bounded roots give finitely many monic integer polynomials). This batch-2 supplier is authored in this run, and the exact obligation used is the instance for the fixed real R=eM≥1 of the argument.

[F6]

For u∈OK× the minimal polynomial mu∈Z[X] is monic of degree [Q(u):Q], which divides n; its complex roots are exactly the numbers ψ(u), where ψ ranges over the Q-embeddings K→C (Minimal-polynomial criterion for algebraic integers, The degree of an intermediate field divides the degree of a finite extension, F-embeddings of F(α) into an algebraically closed field correspond to the distinct roots of mα, Restriction partitions embeddings in a finite tower into extension fibres).

[F7]

A nonzero polynomial of degree at most n over C has at most n distinct roots (A nonzero polynomial of degree n over an integral domain has at most n distinct roots).

[F8]

The kernel of λ∣OK× is finite (Kernel of the unit logarithm is the roots of unity).

[A1]

The Axiom of Choice is assumed; it is used only through the AC-qualified hyperplane lemma [F2] (The Axiom of Choice).

Proof

technique · boundedness of the log image bounds all conjugates of a unit between two positive constants, and the bounded-conjugate polynomials of bounded degree are finite in number
1.1F2

The image λ(OK×) lies in H and is a subgroup of H.

1.2givenalgebra

Since C⊆H is bounded, there is a real M≥0 with ∣xi∣≤M for every x=(xi)∈C and every coordinate i; fix such an M and put R=eM≥1.

2.1F1step 1.2

Let u∈OK× with λ(u)∈C. Then ∣log⁡∣σiu∣∣≤M for every real embedding and ∣2log⁡∣τju∣∣≤M, that is, −M≤log⁡∣σiu∣≤M and −M/2≤log⁡∣τju∣≤M/2.

3.1F4step 2.1

Exponentiating the inequalities of step 2.1, using that the exponential is strictly increasing and inverse to the logarithm, gives e−M≤∣σiu∣≤eM=R for every real embedding and e−M/2≤∣τju∣≤eM/2 for every complex embedding; in particular every conjugate of u has modulus at most R.

4.1F5F6F7step 3.1

Consequently the minimal polynomial mu of such a unit u is a monic integer polynomial of degree at most n all of whose complex roots have modulus at most R; by [F5] there are only finitely many such polynomials, and each of them has at most n distinct complex roots by [F7], so the set S:={u∈OK×:λ(u)∈C} is finite.

5.1F3step 1.1step 4.1step 1.2

The intersection C∩λ(OK×) is the image under λ of S, hence is finite; therefore every bounded subset of H meets the subgroup λ(OK×) in a finite set, and by the lattice criterion [F3] the subgroup λ(OK×) is discrete.

6.1A1F8step 5.1∎

The single Choice use is [A1] through the AC-qualified product formula behind the hyperplane lemma; the bounded-conjugate and root-bound arguments select nothing, and the kernel [F8] is finite by the choice-free finiteness of the roots of unity.

Depends on

Used by

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Sources