Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-08-11
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  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
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A nonzero polynomial of degree n over an integral domain has at most n distinct roots

Statement

Let D be an integral domain. A nonzero polynomial f∈D[x] of degree n has at most n distinct roots in D.

Facts & Assumptions

Given: An integral domain D and a nonzero polynomial f∈D[x] of degree n.

[L1]

If a is a root of f, then f=(x−a)q for some polynomial q (Factor theorem over a commutative ring).

[L2]

Degrees add when nonzero polynomials over a domain are multiplied (Over an integral domain, degrees add under multiplication of nonzero polynomials).

[L3]

In an integral domain, a product is zero only if one factor is zero (Zero divisor, and integral domain: a commutative ring with 1≠0 and no zero divisors).

[L4]

If a property holds at 0 and passes from n to n+1, it holds for every natural number (The principle of mathematical induction).

Proof

technique · induction
1.1

If n=0, then f is a nonzero constant and has no root, proving the base case.

basegiven
2.1

For n>0, if f has no root the claim is immediate; otherwise choose a root a, use [L1] to write f=(x−a)q, and use [L2] to obtain deg⁡q=n−1.

step 1.1ihL1L2choose
3.1

If b≠a is another root, then 0=f(b)=(b−a)q(b), and [L3] gives q(b)=0 because b−a≠0; the induction hypothesis bounds the roots other than a by n−1, so f has at most n roots, and [L4] completes the induction.

step 2.1ihL3L4discharge-induction∎

Depends on

Used by

Dependency tree · two levels

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Sources