Alphabeta Math
TheoremStatement: Literature-sourcedProof: Literature-sourcedprecheck passaudited 2026-08-11
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Over an integral domain, degrees add under multiplication of nonzero polynomials

Statement

If R is an integral domain and f,g∈R[x] are nonzero, then fg≠0 and

deg⁡(fg)=deg⁡f+deg⁡g,lc⁡(fg)=lc⁡(f)lc⁡(g).

Facts & Assumptions

Given: An integral domain R and nonzero polynomials f,g∈R[x].

[L1]

The coefficient of degree deg⁡f+deg⁡g in fg is the product of the two leading coefficients, and all higher coefficients vanish (Degree inequalities for sums and products over a commutative ring).

[L2]

In an integral domain, a product of two nonzero elements is nonzero (Zero divisor, and integral domain: a commutative ring with 1≠0 and no zero divisors).

Proof

technique · direct
1.1

The leading coefficients of f and g are nonzero, so [L2] makes their product nonzero.

givenL2
2.1

Fact [L1] identifies that product as the coefficient at degree deg⁡f+deg⁡g and makes every higher coefficient zero, so fg≠0, its degree is the sum of the degrees, and its leading coefficient is the product of the leading coefficients.

step 1.1L1∎

Depends on

Used by

Dependency tree · two levels

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Sources