Alphabeta Math
LemmaStatement: Literature-sourcedProof: Literature-sourcedprecheck passaudited 2026-08-11
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Every nonzero nonunit polynomial over a field factors into irreducible polynomials

Statement

Every nonzero nonunit polynomial over a field is a finite product of irreducible polynomials.

Facts & Assumptions

Given: A field F and a nonzero nonunit polynomial f∈F[x].

[L1]

A nonzero nonunit is irreducible when every factorization has a unit factor (Irreducible and prime elements of an integral domain).

[L2]

Degrees add under multiplication of nonzero polynomials over a field (Over an integral domain, degrees add under multiplication of nonzero polynomials).

[L3]
[L4]

Strong induction proves a natural-number property once the case at n follows from all smaller cases (Strong (complete) induction).

Proof

technique · induction
1.1

Use strong induction on n=deg⁡f; by [L3], a nonzero nonunit has n≥1.

basegivenL3L4
2.1

If f is irreducible, it is already a one-factor product; otherwise [L1] gives f=gh with g,h nonunits, and neither is zero because f≠0.

step 1.1ihL1construct
3.1

By [L2], deg⁡g and deg⁡h are positive and strictly below n, so the induction hypotheses factor both into irreducibles; concatenating those factorizations gives one for f, and [L4] completes the induction.

step 2.1ihL2L3L4discharge-induction∎

Depends on

Used by

Dependency tree · two levels

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Sources