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PropositionStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-08-16
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  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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A field with q elements is the splitting field of xq−x over its prime subfield

Statement

If F is a field with q elements, then every a∈F satisfies aq=a, and F is the splitting field of tq−t over its prime subfield.

Facts & Assumptions

Given: A finite field F of order q.

[L3]

A splitting field is generated over the base by all roots of the polynomial (Polynomials that split and splitting fields of a polynomial or a family of polynomials).

[L4]

A nonzero degree-q polynomial over a domain has at most q distinct roots (A nonzero polynomial of degree n over an integral domain has at most n distinct roots).

Proof

technique · direct
1.1givenL1algebra

The cyclic group F× has order q−1, so every nonzero a∈F satisfies aq−1=1 and hence aq=a. The equality also holds for a=0.

2.1step 1.1L4

Thus all q elements of F are roots of tq−t. By [L4] there are no other distinct roots in any extension, so the polynomial splits into its linear factors over F.

3.1step 2.1L3∎

The set of roots is all of F, so it generates F over its prime subfield. By [L3], F is the splitting field.

Depends on

Used by

Dependency tree · two levels

13 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources