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PropositionStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passaudited 2026-08-16
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A field with q elements is the splitting field of xqx over its prime subfield

Statement

If F is a field with q elements, then every aF satisfies aq=a, and F is the splitting field of tqt over its prime subfield.

Facts & Assumptions

Given: A finite field F of order q.

[L3]

A splitting field is generated over the base by all roots of the polynomial (Polynomials that split and splitting fields of a polynomial or a family of polynomials).

[L4]

A nonzero degree-q polynomial over a domain has at most q distinct roots (A nonzero polynomial of degree n over an integral domain has at most n distinct roots).

Proof

technique · direct
1.1

The cyclic group F× has order q1, so every nonzero aF satisfies aq1=1 and hence aq=a. The equality also holds for a=0.

givenL1algebra
2.1

Thus all q elements of F are roots of tqt. By [L4] there are no other distinct roots in any extension, so the polynomial splits into its linear factors over F.

step 1.1L4
3.1

The set of roots is all of F, so it generates F over its prime subfield. By [L3], F is the splitting field.

step 2.1L3

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 42 results over 13 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources